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natali 33 [55]
3 years ago
15

If the difference in electronegativity values between two atoms is more than 2.0, nonpolar covalent bonds generally form.

Physics
1 answer:
Advocard [28]3 years ago
4 0
It’s False I think :))
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How are science and technology the same
Ilia_Sergeevich [38]

Answer:

Science is the study of the natural world by collecting data through a systematic process called the scientific method. And technology is where we apply science to create devices that can solve problems and do tasks. Technology is literally the application of science

Explanation:

3 0
3 years ago
A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hai
tekilochka [14]

Answer:

900 W.      

Explanation:

Given that

Electric heater 1500 W

We know that power P given as

P= V I

So the total power of 120 V and 20 A circuit

P = 120 x 20

P= 2400 W

So the power new load P'

P'= Total system power(P)- Electric heater load

P ' = 2400 - 1500

P'= 900 W

So the answer is 900 W.

6 0
3 years ago
Why should a physical quantity be measured?​
Natasha_Volkova [10]

Answer:

It allows us to understand nature much more deeply than does qualitative description alone.

Explanation:

Without explaining the measurements, a quantity cannot always be measured.

Hope this helped, and please mark as Brainliest :)

8 0
3 years ago
a rifle is fired and recoils when the bullet leaves the gun. this is an example of newton's 3rd law. the force on the bullet is.
Alex_Xolod [135]
The force of the bullet is the same.
3 0
3 years ago
Read 2 more answers
A circular grill of diameter 0.25 m has an emissivity of 0.8. If the surface temperature is maintained at 150°C, determine the r
Schach [20]

Answer:

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

Explanation:

Power required to maintain the surface temperature at 150°C from 20°C

P= εσA(T^4-t^4)

P= power in watt

ε= emissivity

A=  area of surface

T= 150°C= 423 K

t= 20°C= 303K

/sigma= 5.67×10^{-8} watt/m^2K^4

putting vales we get

= 0.8\times5.67\times10^{-8} \pi\frac{0.25^4}{4}(423^4-303^4)

P=52.51822 Watt

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

4 0
3 years ago
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