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11111nata11111 [884]
3 years ago
12

A 2.0 kg hanging mass stretches a coiled spring by 0.15 m. The spring constant, k, is: (A) 0.075 N/m, (B) 2.9 N/m (C) 131 N/m, (

D) 1,742 N/m, (E) none of the above.
Physics
1 answer:
Alla [95]3 years ago
3 0

Answer:

C

Explanation:

Givens

m = 2 kg

F = 2 * 9.81

F =  19.62 N

x = 0.15 m

Formula

F = k*x

Solution

19.62 = k*0.15

k = 19.62/0.15

k = 130.8 which rounded to the nearest given answer is C

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The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparal
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Answer:

M= 0.4 Am^2

Explanation:

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Generally the equation for the total magnetic moment  M is mathematically given by

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M= I * A

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3 0
3 years ago
An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.
Aleksandr-060686 [28]

The tension in the upper rope is determined as 50.53 N.

<h3>Tension in the upper rope</h3>

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

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  • T(d) is tension in lower rope

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T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

Learn more about tension here: brainly.com/question/918617

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6 0
2 years ago
An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirro
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Now that we have the value of p, we can plug it into the magnification equation.

M=-16/13.33=1.2
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So the height of the image produced by the mirror is 9.6cm.
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The velocity of the ball is 30.0 m/s.
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