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timofeeve [1]
3 years ago
8

Radio signals travel at a rate of 3 × 108 meters per second. how many seconds would it take for a radio signal to travel from a

satellite to the surface of earth if the satellite is orbiting at a height of 9.6 × 106 meters? (hint: time is distance divided by speed.)
Physics
1 answer:
nlexa [21]3 years ago
6 0
<span>3.2x10^-2 seconds (0.032 seconds)
   This is a simple matter of division. I also suspect it's an exercise in scientific notation, so here is how you divide in scientific notation:

   9.6 x 10^6 m / 3x10^8 m/s

   First, divide the significands like you would normally.
 9.6 / 3 = 3.2

   And subtract the exponent. So
 6 - 8 = -2

   So the answer is 3.2 x 10^-2
 And since the significand is less than 10 and at least 1, we don't need to normalize it.

   So it takes 3.2x10^-2 seconds for the radio signal to reach the satellite.</span>
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Answer: q2 = -0.05286

Explanation:

Given that

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15046153.85 = 8.99×10^9q/5.62^2

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