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3 years ago

I need help please so fast

Physics

1 answer:

Simora [160]3 years ago

7 0

Answer:

DUumb

Explanation:

Duumb

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Which statement is true?

Fynjy0 [20]

If it's Kepler's law of equal areas you're talking about,
then the first of the four statements is true.

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how much water is needed to produce 1kwh of electricity at a power plant that is 30% efficient if the temperature increase 10 C

Dimas [21]

The amount of water needed is 287 kg

Explanation:

The amount of energy that we need to produce with the power plant is

$E=1 kWh = (1000W)(1h)=(1000W)(3600s)=3.6\cdot 10^6 J$

We also know that the power plant is only 30% efficient, so the energy produced in input must be:

$E_{in}=\frac{E}{0.30}=\frac{3.6\cdot 10^6}{0.3}=1.2\cdot 10^7 J$

The amount of water that is needed to produce this energy can be found using the equation

$E_{in}=mC\Delta T$

where:

m is the amount of water

$C=4186 J/kg^{\circ}C$ is the specific heat capacity of water

$\Delta T=10^{\circ}C$ is the increase in temperature

And solving for m, we find:

$m=\frac{E_{in}}{C\Delta T}=\frac{1.2\cdot 10^7}{(4186)(10)}=287 kg$

Learn more about specific heat capacity:

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2 years ago

Fluorine has 7 valence electrons. Which charge is its ion likely to have?(1 point)

7nadin3 [17]

Answer:

1–

Explanation:

The fluorine is the element with biggest electronegativity in the periodic table, so it usually always take an electron and gets charge 1–

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2 years ago

What is the restoring force of a spring stretched 0.35 meters with a spring contact of 55 newtons?

Vesna [10]

F=-kx = -19,25 answer D

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3 years ago

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Uphill escape ramps are sometimes provided to the side of steep downhill highways for trucks with overheated brakes. For a simpl

o-na [289]

Answer:

404.4 m

Explanation:

Converting the initial speed from km/h to m/s then

$140\times \frac {1000m}{3600s}=38.88888889 m/s \approx 38.89 m/s$

The acceleration is resolved as shown in the figure hence

deceleration of the truck along the inclined plane will be

$a=-g sin \theta$ where g is acceleration due to gravity

Substituting g with $9.81 m/s^{2}$ then

$a=-9.81 m/s^{2} sin 11^{\circ}=-1.871836245\approx -1.87 m/s^{2}$

Using kinematic equation

$v^{2}=u^{2}+2as$ and making s the subject then

$s=\frac {v^{2}-u^{2}}{2a}$ where v and u are final and initial velocities respectively

Substituting 0 for v, 38.89 m/s for u and $-1.87 m/s^{2}$ then

$s=\frac {0^{2}-38.89^{2}}{2\times -1.87}=404.3936096 m\approx 404.4 m$

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2 years ago