All categories

3 years ago

Which of the following is an example of how pictures of a planet's surface can provide evidence about the planet's natural

Chemistry

1 answer:

crimeas [40]3 years ago

8 0

Answer:

Explanation:

Pictures of valleys suggest the present of water because there are limited ways that valleys can form. Those formed in the presence of water have distinctive characteristics that differentiate them from those formed by other processes.

For example, a U-shaped valley will have been carved by a large mass of ice, so we know there is (or was) frozen water on the surface of the planet at some point. V-shaped valleys with lines that resemble veins are tributaries running into them could be active or dried up river valleys.

Other valleys are caused by wind and by geologic processes such as divergent plate boundaries and faulting, but these do not resemble those carved by water.

You might be interested in

If 5 L of butane is reacted what volume of carbon dioxide is produced ILL GIVE BRAINLIEST

Len [333]

Answer: First, here is the balanced reaction: 2C4H10 + 13O2 ===> 8CO2 + 10H2O.

This says for every mole of butane burned 4 moles of CO2 are produced, in other words a 2:1 ratio.

Next, let's determine how many moles of butane are burned. This is obtained by

5.50 g / 58.1 g/mole = 0.0947 moles butane. As CO2 is produced in a 2:1 ratio, the # moles of CO2 produced is 2 x 0.0947 = 0.1894 moles CO2.

Now we need to figure out the volume. This depends on the temperature and pressure of the CO2 which is not given, so we will assume standard conditions: 273 K and 1 atmosphere.

We now use the ideal gas law PV = nRT, or V =nRT/P, where n is the # of moles of CO2, T the absolute temperature, R the gas constant (0.082 L-atm/mole degree), and P the pressure in atmospheres ( 1 atm).

V = 0.1894 x 0.082 x 273.0 / 1 = 4.24 Liters.

Explanation:

8 0

3 years ago

A rigid tank is divided into two equal volumes. One side contains 2 kmol of nitrogen N2 at 500 kPa while the other side contains

k0ka [10]

Answer:

The partial pressure of the $CO_2$ in the final mixture is 200 kPa.

Explanation:

Pressure of nitrogen gas when the two tanks are disconnected = 500 kPa

Pressure of the carbon-dioxide gas when the two tanks are disconnected = 200 kPa

Moles of nitrogen gas = $n_1= 2 kmol$

Moles of carbon dioxide gas = $n_2=8 kmol$

After connecting both the tanks:

The total pressure of the both gasses in the tank = p = 250 kPa

According to Dalton' law of partial pressure:

Total pressure is equal to sum of partial pressures of all the gases

Partial pressure of nitrogen = $p_{N_2}^o$

Partial pressure of carbon dioxide= $p_{CO_2}^o$

$p_{N_2}^o=p\times \frac{n_1}{n_1+n_2}$

$p_{N_2}^o=250 kPa\times \frac{0.2}{0.2+0.8}=50 kPa$

$p_{CO_2}^o=p\times \frac{n_2}{n_1+n_2}$

$p_{CO_2}^o=250 kPa\times \frac{0.8}{0.2+0.8}=200 kPa$

The partial pressure of the $CO_2$ in the final mixture is 200 kPa.

7 0

3 years ago

For which part of the engineering process would the use of statistics to analyze data about a new drug test be helpful?

Alenkinab [10]

D Testing the solution

8 0

3 years ago

Read 2 more answers

Please help me.. someone

lubasha [3.4K]

The different forms of a gene that decides a characteristic are known as Alleles.

A feature that has different forms in a population are Characteristics.

I believe these are the answers, hope I helped!

6 0

3 years ago

A block of material has a volume of 2m^3. It has a mass of 1 ×10^4 kg. Calculate the density of the material sample and express

Ivenika [448]

Answer:

The answer to your question is: density = 5 g/cm³

Explanation:

Data

Volume = v = 2 m³

mass = m = 1 x 10⁴ kg

Density = d = ? g/cm³

Formula

density = mass/volume

Volume

1 m³ ------------------- 1 000 000 cm³

2 m³ ------------------ x

x = (2 x 1 000 000) / 1

x = 2 000 000 cm³

Mass

1 kg ------------------ 1000 g

1 x 10⁴ kg ------------ x

x = (1 x 10⁴ x 1000) / 1

x = 10 000 000 g

density = (10 000 000) / 2 000 000

density = 5 g/cm³

5 0

3 years ago