Answer:
0.049 mol/L.s
Explanation:
The decomposition of hydrogen peroxide is:
![Rate = -\dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{ 2 \Delta [H_2O_2]}{\Delta t}](https://tex.z-dn.net/?f=Rate%20%3D%20-%5Cdfrac%7B%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D%3D%20%5Cdfrac%7B%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D%3D%20%5Cdfrac%7B%202%20%20%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D)
The rate of decomposition reaction = the rate of formation of 
= 0.098 mol/L.s
∴
Rate of formation of 
= 0.049 mol/L.s
Answer: 0.0738 M
Explanation:
1) Chemical equation:
<span>HNO₃ + LiOH → LiNO₃ + H₂O
</span>
2) Mole ratios:
1 mol HNO₃ neutralizes 1 mol LiOH
3) Number of moles of H⁺ from HNO₃:
M = n / V ⇒ n = M × V = 0.050 liter × M
4) Number of moles of OH⁻ from LiOH
M = n / V ⇒ n = M × V = 0.03690 liter × 0,100 M
5) Equivalence point:
number of moles of H⁺ = number of moles of OH⁻
⇒ 0.0500 × M = 0.03690 × 0.100
⇒ M = 0.03690 × 0.100 / 0.0500 = 0.0738 M
<span />
Answer:
Out of personal experience (lol), I'd say the stick of butter is hard, cold, and very smooth at first. Once heated up or just kept at room temp for a while, it becomes mushy.
Hope I helped! ☺
PV = nRT
P is pressure, V is volume, n is number of moles, R is the gas constant, T is temperature in K
(2.85 atm)(12.5 L) = (n)(.08206)(27 C + 273)
n = 1.45 moles x 35.45 grams / mol Cl2 = 51.3 grams
