Ask question

Ask question

All categories

Tcecarenko [31]

3 years ago

11

A small acting club has 4 members. three of the members are to be chosen for a trip to see a broadway play. how many different 3

-member groups are possible?

1 answer:

Gnesinka [82]3 years ago

8 0

I think the answer is 4 different possibility's.

You might be interested in

A packet of candles and box of matches cost #420. The candles cost 20 times as much as the matches

olga55 [171]

Answer:

candles = $400

matches = $20

Step-by-step explanation:

Let cost of candles = $c

Let cost of matches = $m

c = 20 m (20 times m)

c + m = 420

20m + m = 420

21 m = 420

m = 20

c = 20 (20) = 400

6 0

3 years ago

Ne Shadea part of a whole.

kolbaska11 [484]

Answer:

sorry the equation is confusing

Step-by-step explanation:

and pls fix it and thx.

4 0

3 years ago

How do you do surface area? and this question

marta [7]

Answer:

you take all the point from around then multiply and do the same with the base

Step-by-step explanation:

take 2 times 2.8
12 times 4
4 times 4
add them all

6 0

4 years ago

Read 2 more answers

Each week Suzanne and Sarah drink 2 gallons of milk.HGow many iounces of milk do they drink each Week ?

Ray Of Light [21]

G = 128 fl oz
128 * 2 = 256

3 0

3 years ago

Find the similarity ratio and the ratio of perimeters for two regular octagons with areas of 18in2 and 50in2

sweet-ann [11.9K]

Answer:

3. 3 : 5; 3: 5

Step-by-step explanation:

First, let's find the leght of the sides of each octagon.

$A= 18in^{2}$

The area of an octagon is defined by

$A=2(1+\sqrt{2})l^{2}$

Replacing the area

$18=2(1+\sqrt{2})l^{2}\\\frac{18}{2(1+\sqrt{2})} =l^{2}\\l=\sqrt{\frac{18}{3.4} } \approx 2.3 \ in$

Therefore, the side of the first octagon is 1.6 inches long.

Its perimeter is: $P=8(2.3in)=18.4in$

$A=50 in^{2}$

$50=2(1+\sqrt{2})l^{2}\\\frac{50}{2(1+\sqrt{2})} =l^{2}\\l=\sqrt{\frac{50}{3.4} } \approx 3.8 \ in$

Therefore, the side of the second octagon is 3.8 inches long.

Its perimeter is $P=8(3.8in)=30.4in$ .

Now, let's divide to find each ratio:

$\frac{3.8}{2.3} \approx 1.65$ (the ratio between sides).

$\frac{30.4}{18.4} \approx 1.65$ (the ratio between perimeters).

Therefore, the closest ratio is 3. 3 : 5; 3: 5

8 0

3 years ago

Read 2 more answers