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dangina [55]
3 years ago
10

A chemical engineer must report the average volume of a certain pollutant produced by the plants under her supervision. Here are

the data she has been given by each plant: plant volume of pollutant Macon 0.519 LAllegheny 44.67 LDoheny 0.826 LWhat average volume should the chemical engineer report? Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

The chemical engineer should report average volume of 15.34 L.

Explanation:

Volume of Macon = 0.519 L

Volume of Allegheny = 44.67 L

Volume of Doheny = 0.826 L

Average of the volume of the pollutants:

\frac{0.519 L+44.67 L+ 0.826L}{3}=\frac{46.015 L}{3}=15.33833 L

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

Here the 44.67  has two significant digit after decimal point.So the answer will be reported as in with 2 significant figures after decimal point.

15.33833 L\approx 15.34 L

The chemical engineer should report average volume of 15.34 L.

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Calculate the pH of a solution in which [OH–] = 4.5 × 10–9M.
posledela

Answer:

5.65 is the pH.

Explanation:

I am assuming that you are asking for confirmation on your answer. The answer is 5.65.

You would do:

[pOH] = -log[OH-]

          = -log[4.5*10^-9]

         equals about 8.3468

To find pH your would subtract the pOH from 14.

14-8.3468 = 5.65 << Rounded to match the answer choices.

7 0
3 years ago
If a gas in a closed container is pressurized from 15.0 atmospheres to 16.0
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Answer:

T₂ = 317.87 K

Explanation:

Given data:

Initial pressure = 15 atm

Final pressure = 16 atm

Initial temperature = 298 K

Final temperature = ?

Solution:

According to Gay-Lussac Law,

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Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

15 atm / 298K = 16 atm/T₂

T₂ = 16atm × 298 K / 15 atm

T₂ = 4768 atm. K / 15 atm

T₂ = 317.87 K

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