Answer : The normal boiling point of ethanol will be, 
or 
Explanation :
The Clausius- Clapeyron equation is :
where,
= vapor pressure of ethanol at 
= 98.5 mmHg
= vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg
= temperature of ethanol = 
= normal boiling point of ethanol = ?
= heat of vaporization = 39.3 kJ/mole = 39300 J/mole
R = universal constant = 8.314 J/K.mole
Now put all the given values in the above formula, we get:
Hence, the normal boiling point of ethanol will be, or
Answer:
The answer to your question is: $ 35.6
Explanation:
C₆H₁₂N₂O₄Pt
Platinum = 52.5 %
Price = $1047 / troy ounce
cost of platinum = ? of 2 g
1 troy ounce = 480 grains
1 grain = 64.8 mg
Process
Get 52.5 % of 2 g
2 g ----------------- 100 %
x ----------------- 52.5%
x = (52.5 x 2) / 100
x = 1.05 g
1 g --------------------- 1000 mg
1.05 g ---------------- x
x = 1050 mg of Pt
1 grain ---------------- 64.8 mg
x --------------- 1050 mg
x = 16.2 grains
480 grains ---------------- 1 troy ounce
16.2 grains ---------------- x
x = (16.2 x 1) / 480
x = 0.034 troy ounce
$ 1047 ------------------ 1 troy ounce
x ------------------- 0.034
x = (0,034 x 1047) / 1
x = $ 35.6
Answer:
No more than 0.1 mL of hydrochloricton acid
Answer:
The answer to your question is 122.4 g of O₂
Explanation:
Data
mass of O₂ = ?
moles of H₂O = 7.65
Process
1.- Write the balanced chemical reaction
2H₂O ⇒ 2H₂ + O₂
2.- Convert the moles of H₂O to grams
molar mass of H₂O = 2 + 16 = 18 g
18 g of H₂O ---------------- 1 mol
x ----------------- 7.65 moles
x = (7.65 x 18) / 1
x = 137.7 g H₂O
3.- Calculate the grams of O₂
36 g of H₂O -------------------- 32 g of O₂
137.7 g of H₂O ------------------- x
x = (32 x 137.7) / 36
x = 122.4 g of O₂
