Answer: b.) they tend to lose electrons to gain stability
Explanation:
The answer is (3) HClO. In the Cl2, chlorine has an oxidation number of zero. In HCl, the oxidation number is -1. In HClO2, the oxidation number is +3. In HClO, it is +1. You can calculate this by using O with oxidation number of -2 and H with +1.
Answer:
All of the above processes have a ΔS < 0.
Explanation:
ΔS represents change in entropy of a system. Entropy refers to the degree of disorderliness of a system.
The question requests us to identify the process that has a negative change of entropy.
carbon dioxide(g) → carbon dioxide(s)
There is a change in state from gas to solid. Solid particles are more ordered than gas particles so this is a negative change in entropy.
water freezes
There is a change in state from liquid to solid. Solid particles are more ordered than liquid particles so this is a negative change in entropy.
propanol (g, at 555 K) → propanol (g, at 400 K)
Temperature is directly proportional to entropy, this means higher temperature leads t higher entropy.
This reaction highlights a drop in temperature which means a negative change in entropy.
methyl alcohol condenses
Condensation is the change in state from gas to liquid. Liquid particles are more ordered than gas particles so this is a negative change in entropy.
A homogeneous mixture is a solid, liquid or gaseous mixture that has the same proportions of its components throughout any given sample & a heterogeneous mixture has components in which proportions vary throughout the sample. They are both similar because they’re often referred to as solutions
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Answer:</h3>
43.33 atm
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Explanation:</h3>
We are given;
Mass of C₆H₆ = 26.2 g
Volume of the container = 0.25 L
Temperature = 395 K
We are required to calculate the pressure inside the container;
First, we calculate the number of moles of C₆H₆
Molar mass of C₆H₆ = 78.1118 g/mol.
But; Moles = mass ÷ Molar mass
Moles of C₆H₆ = 26.2 g ÷ 78.1118 g/mol.
= 0.335 moles C₆H₆
Second, we calculate the pressure, using the ideal gas equation;
Using the ideal gas equation, PV = nRT , Where R is the ideal gas constant, 0.082057 L.atm/mol.K
Therefore;
P = nRT ÷ V
= (0.335 mol × 0.082057 × 395 K) ÷ 0.25 L
= 43.433 atm
Therefore, the pressure inside the container is 43.33 atm
