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Scorpion4ik [409]
3 years ago
5

What is the total number of atoms in a molecule of CH3OH? one three four six

Chemistry
2 answers:
masya89 [10]3 years ago
6 0
Six !

Just count each element in the molecule (Since there are 4 hydrogen atoms, a carbon and an oxygen atom in this molecule of methanol.)
qwelly [4]3 years ago
5 0

<u>Answer:</u> The correct answer is six.

<u>Explanation:</u>

The chemical name for the given chemical formula is methanol. This is an organic compound in which a covalent bond is present between hydrogen and carbon atom.

In a single mole of this compound, there are 3 different types of elements are present. The elements are carbon, hydrogen and oxygen.

In 1 mole of methanol, 1 mole of carbon atom, 4 moles of hydrogen atoms and 1 mole of oxygen atoms are present.

Thus, in total 6 atoms are present in 1 mole of methanol molecule.

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I need help on this please
tino4ka555 [31]

Answer:

The answer is c

Explanation:c

3 0
3 years ago
A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
vodka [1.7K]

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t  1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= \frac{w}{W} = \frac{w}{V}= density

P = \frac{density RT}{M}       density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm

putting the values in reaction

0.75 = \frac{0.525 x 0.0821 x 608.15 }{M}

  M    = 34.61

         

to calculate the Kc

Kc=\frac{ [NO] [O2]}{NO2}

  \frac{1-2x}{1+x} x M NO2 + \frac{2x}{1+x} M NO+ \frac{x}{1+x} M O2

Putting the values as molecular weight of NO2, NO,O2

\frac{46(1-2x) +30(2x)+32x}{1+x}

34.61= \frac{46}{1+x}

x= 0.33

Kc= \frac{4x^2)x}{1-2x^2}

    putting the values in the above equation

Kc = 0.00662

     

5 0
3 years ago
Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0
3 years ago
Calculate concentration of methylene blue . Give answer in molarity. concentration in ppm=4.8
PSYCHO15rus [73]

Answer:

The molarity of methylene blue is 1.5 × 10⁻⁵ M

Explanation:

When we talk about aqueous solutions, 1 ppm means 1 mg of solute per liter of solution. We need to express this concentration in molarity, which is moles of solute per liter of solution. To convert mass to moles we need the molar mass of methylene blue(MB), which is 320 g/mol.

Then,

\frac{4.8mgMB}{1Lsolution} .\frac{1gMB}{10^{3}mgMB } .\frac{1molMB}{320gMB} =1.5 \times 10^{-5} M

8 0
4 years ago
Which of the following is TRUE about enzymes?
Vinil7 [7]

Answer:

All options are correct.

Explanation:

All options are correct.

Enzymes being faster, than chemical catalysts and their reaction rate is almost 10 times faster.They are highly specific producing large amount of good residues and can work at mild conditions, physiological pH and temperature.

They can be regulated by other molecules that either increase or reduce their activity.

Molecules that increase the activity of an enzyme are called activators, while molecules that decrease the activity of an enzyme are called inhibitors.

6 0
4 years ago
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