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alina1380 [7]
2 years ago
5

Determine the number of moles of a gas which occupies 39.0mL at 27°C if the pressure is 107 kPa.

Chemistry
1 answer:
Aloiza [94]2 years ago
8 0
We can use the ideal gas law equation to solve for the number of moles present 
PV = nRT
P - pressure - 107 kPa
V - 39.0 x 10⁻⁶ m³
n - number of moles 
R - 8.314 Jmol⁻¹K⁻¹
T - temperature in K - 27 °C + 273 = 300 K
Substituting these values into the equation
107 000 Pa x 39.0 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K
n = 1.67 x 10⁻³ mol
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When molecules have a shorter bond length does it take more or less energy to break the chemical bond between those atoms?
Sloan [31]

Answer:

more energy

Explanation:

shorter lengths in bonds require more energy because atoms are strongly connected in short length bonds

7 0
3 years ago
One year ago, you sold a put option on 100,000 euros with an expiration date of 1 year. you received a premium on the put option
pochemuha
There are two problems for this question:1. What is the total dollar amount of your profit and loss:
Put option premium is equal to 0.04 per unit.
The exercise price is 1.22
One option contract is 100,000
Selling price is 1.20
-Purchase prise is - 1.22
-Premium paid is +0.04
Net profit is = 0.02 x 100,000 = 2,000 – 80 = 1,920

2. Now undertake that as an alternative of taking a position in the put option one year ago, you sold a future's contract on 100,000 euros with a payment date of one year.
Find the total dollar amount of your profit or loss.
Solution: Contract to buy: $1.20 x 100,000 = 120,000 at payment date.
Contract to sell: $1.22 x 100,000 = 122,000 at settlement date
Settle contracts: -2,000 - 80 = -$2,080
5 0
3 years ago
Provide the IUPAC names for
ollegr [7]

<u>Answer:</u>

<u>For a:</u> The IUPAC name of the compound is N-ethylethaneamide.

<u>For b:</u> The IUPAC name of the compound is N,N-diethylmethaneamide.

<u>For c:</u> The IUPAC name of the compound is ethyl pentanoate

<u>Explanation:</u>

To name a compound, first look for the longest possible carbon chain.

  • <u>For a:</u>

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is R-CO-NH_2, where R is an alkyl or aryl group.

In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'

Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N-ethylethaneamide.

  • <u>For b:</u>

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is R-CO-NH_2, where R is an alkyl or aryl group.

In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'

Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.

  • <u>For c:</u>

Esters are a kind of organic molecules having functional groups, R-COO-R' where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'

Also, an ethyl group forms the alcoholic part.

Hence, the IUPAC name of the compound is ethyl pentanoate

6 0
2 years ago
Which statement correctly describes an atom of the element helium
Assoli18 [71]
Is this a multiple choice? Anyways I will just give you a written answer and hopefully it helps.

A: Helium is made up of two electrons held by electromagnetic force to two protons that are inside of a nucleus along with one or two neutrons.
5 0
3 years ago
Oxygen has an electronegativity of 3.4, phosporus has an electronegativity of 2.2 The bond between them is
Ipatiy [6.2K]

Answer:

B. polar covalent

Explanation:

7 0
3 years ago
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