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3 years ago

Determine the number of moles of a gas which occupies 39.0mL at 27°C if the pressure is 107 kPa.

1 answer:

8 0

We can use the ideal gas law equation to solve for the number of moles present
PV = nRT
P - pressure - 107 kPa
V - 39.0 x 10⁻⁶ m³
n - number of moles
R - 8.314 Jmol⁻¹K⁻¹
T - temperature in K - 27 °C + 273 = 300 K
Substituting these values into the equation
107 000 Pa x 39.0 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K
n = 1.67 x 10⁻³ mol

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3 years ago

For the reaction below, complete the rate expression that relates the change in concentration with respect to time to the rate o

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Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

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The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

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3 years ago

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3 years ago

If 0.089 grams of KI is dissolved in 500g of H2O, what is the concentration of the resulting solution in parts per million?

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Answer:

The concentration of the resulting solution in parts per million is 177.97

Explanation:

Parts per million (ppm), is a unit of measure for concentration that refers to the number of units of the substance per million units of the set.

The concentration in parts per million expressed in mass / mass is calculated by dividing the mass of the solute (ms) by the mass of the solution (md, sum of the mass of the solute and the mass of the solvent), both expressed in the same unit and multiplied by 10⁶ (1 million).

$ppm=\frac{ms}{md} *10^{6}$

So, being:

ms: 0.089 grams of KI

md: 0.089 grams of KI + 500 grams of H₂O= 500.089 grams

Replacing:

$ppm=\frac{0.089 grams}{500.089 grams}*10^{6}$

ppm= 177.97

The concentration of the resulting solution in parts per million is 177.97

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3 years ago