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deff fn [24]
2 years ago
15

How does a car safely transfer the kinetic energy of the passenger and the car?

Chemistry
1 answer:
Yanka [14]2 years ago
5 0
Energy transfer is an extension of Newton’s Laws. Energy cannot be created nor destroyed; it can only be transferred. The moving body has energy, called kinetic energy, and this energy will be transferred into something else as the body slows. Likewise, the car crashing into you will transfer its kinetic energy to you. The other type of energy is potential energy, or stored energy. Think of a spring. When you pull it, you are storing energy. When you let it go, this potential energy is transferred into kinetic energy as motion. Car manufacturers engineer a purposeful flaw into the structure, the Crumble Zone. This Crumble Zone is a structurally assigned place for kinetic energy to be transferred into potential energy in the case of an accident. When two cars collide, the kinetic energy is used up to fold the metal of the auto, keeping the destructive energy out of the passengers. The same science is behind the recommendation that motorcyclists wear helmets and body armor. Auto crumble zones, as well as air bags, helmet foam and Kevlar, are all methods for converting harmful kinetic energy into safe potential energy.
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The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e
Sunny_sXe [5.5K]

Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

           N_{2}O_{4} \rightarrow 2NO_{2}

Let us assume that x concentration of N_{2}O_{4} is present at the initial stage. Therefore, according to the ICE table,

                    N_{2}O_{4} \rightarrow 2NO_{2}

Initial :               x                   0

Change :       - 0.1        2 \times 0.1

Equilibrium : (x - 0.1)             0.2

Now, expression for K_{p} of this reaction is as follows.

     K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

Putting the given values into the above formula as follows.

          K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

                 2 = \frac{(0.2)^{2}}{(x - 0.1)}

                2 \times (x - 0.1) = (0.2)^{2}

                            x = 0.12

This means that P_{N_{2}O_{4}} = x = 0.12 atm.

Thus, we can conclude that the initial pressure in the container prior to decomposition is 0.12 atm.

6 0
3 years ago
Balance this equation: Al+ HNO3 ---- H2 + Al(NO3)3​
romanna [79]

Answer:

2Al+ 6HNO3 ---- 3H2 + 2Al(NO3)3​

Explanation:

Put coefficient a,b,c, and d for calculation:

a Al + b HNO3 = c H2 + d Al(NO3)3

for Al: a = d

for H: b = 2c

for N: b = 3d

for O: 3b = 9d

Suppose a=1, then d=1, b=3, c=3/2

multiply 2 to make all natural number, a=2, then b=6, c=3, d=2

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