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Aleks04 [339]
3 years ago
13

Air pressure is measured in pascals. For a professional American football game, the ball should be inflated to about 90,000 pasc

als. Scientists studied the effects of air temperature on the pressure inside American footballs by taking these steps: 1. Prepare 100 footballs. 2. Measure each football's air pressure. 3. Divide footballs into 10 groups. 4. Place the groups in different lockers cooled to different air temperatures. 5. After 12 hours, remove the footballs from lockers. 6. Measure each football's pressure again. 7. Compare the new pressures to the starting pressures. What two terms best describe the variable "air pressure inside the football" in this experiment? independent, qualitative independent, quantitative dependent, qualitative dependent, quantitative
Chemistry
2 answers:
GarryVolchara [31]3 years ago
4 0

Answer:

dependent variable the right one is d

Explanation:

i just did it

Komok [63]3 years ago
3 0

Answer: The variable "air pressure inside the football" in this experiment is quantitative and dependent variable.

Explanation:

In the experiment, the scientist filled the foot balls with fix quantity of pressure which then kept for 12 hours . After 12 hours the pressure inside the footballs was again measured. Pressure here is a quantitative variable.

Since, air of temperature is an independent variable. Pressure being dependent variable depends upon the temperature of the air.

Independent variable ; The variable which does not depends upon any other variable.

Dependent variable ; The variable which depends upon independent variable or varies with change independent variable..

Qualitative variables are are the variables which cannot be expressed in form of numbers. They generally convey the characteristic ,category ,quality or type.

Where as Quantitative variable are the variables which can be expressed in the form of number.These are the variables which exist along the continuous sequence.

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Which compounds can be made with the reaction benzene via electrophilic aromatic substitution using isopropyl chloride and AlCl3
Hitman42 [59]

Answer:

isopropyl benzene (cumene)

Explanation:

The reaction of isopropyl chloride and AlCl3 and benzene belongs to the class of organic reactions known as the Friedel Kraft alkylation.

The mechanism of the reaction involves the formation of a tetrahedral complex [AlCl4]^-.

The electrophile now is the isopropyl group which attacks the benzene to yield the product.

4 0
3 years ago
Which direction will the following reaction (in a 5.0 L flask) proceed if the pressure of CO_2(g) is 1.0 atm? CaCO_3(s) rightarr
storchak [24]

Answer:

d. To the left because Q > K_p

Explanation:

Hello,

In this case, for the given reaction:

CaCO_3(s) \rightarrow CaO(s) + CO_2(g)

The pressure-based equilibrium expression is:

Kp=p_{CO_2}

In such a way, since Kp is given we rather compute the reaction quotient at the specificed pressure of carbon dioxide as shown below:

Q=p_{CO2}=1.0

Therefore, since Q>Kp we can see that there are more products than reactants, which means that the reaction must shift leftwards towards the reactants in order to reestablish equilibrium, thus, answer is d. To the left because Q > Kp.

Regards.

6 0
3 years ago
Draw a picture of the moon and sun illustrating the full moon phrase
jek_recluse [69]

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6 0
3 years ago
Read 2 more answers
Suppose a 250. mL flask is filled with 0.30 mol of N_2 and 0.70 mol of NO. The following reaction becomes possible:N_2(g) +O2 →
Inessa [10]

Answer:

0.4 M

Explanation:

Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.

Because there's no O₂ in the beginning, the NO will decompose:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.30 0 0.70 Initial

+x +x -2x Reacts (the stoichiometry is 1:1:2)

0.30+x x 0.70-2x Equilibrium

The equilibrium concentrations are the number of moles divided by the volume (0.250 L):

[N₂] = (0.30 + x)/0.250

[O₂] = x/0.25

[NO] = (0.70 - 2x)/0.250

K = [NO]²/([N₂]*[O₂])

K = \frac{(\frac{0.70 -2x}{0.250})^2 }{\frac{0.30+x}{0.250}*\frac{x}{0.250} }

7.70 = (0.70-2x)²/[(0.30+x)*x]

7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)

4x² - 2.80x + 0.49 = 2.31x + 7.70x²

3.7x² + 5.11x - 0.49 = 0

Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70

x = 0.09 mol

Thus,

[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M

3 0
3 years ago
An increase in which property would cause an electromagnetic wave's energy
patriot [66]
C. Answer correct I think…
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