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olasank [31]
4 years ago
8

A buffered solution containing dissolved aniline, c6h5nh2, and aniline hydrochloride, c6h5nh3cl, has a ph of 5.75.

Chemistry
1 answer:
Semmy [17]4 years ago
7 0
2.13 would be your answer
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Concentration in soil: if a 100-g sample of soil contains 10-5 g of toxaphene, what are the toxaphene soil concentrations report
choli [55]

Toxaphene is a kind of pesticides used to protect crops specially cotton crops.

It is present in both solid and gas form.

It has a piney odor.

The physical appearance of toxaphene is yellow in colour amber waxy form.

It is an organochloride insecticide.

In 1940 it was manufactured.

It is a different composition of 670 chemicals.

According to questions,

Given,

Mass of toxaphene = 10^-5 gm

Mass of soil = 100 gm

Toxaphene soil concentrations = 10^-5 / 100 = 10^-7 gm/gm

1 gm/gm = 109 ppb

Concentration in units of ppb =10^-7 * 109 ppb = 100 ppb

To know more about toxaphene here :

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1 year ago
The most dangerous form of skin cancer which is often caused by over exposure to ultraviolet radiation is what?
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UV exposure that leads to sunburn is proven in developing melanoma, the most dangerous of the three most common types of skin cancer.
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3 years ago
Which property of water helps it move upward by capillary action
zhannawk [14.2K]
It’s the water method that helps it
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H2SO4(aq)+NaOH(s)> (neutralization of both acidic protons)
RUDIKE [14]

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3 years ago
6. A balloon filled with air has a volume of 3.25 L at 30°C. It is placed in a freezer at
Viefleur [7K]

Answer:

2.82 L

T₁ = 303 K

T₂ = 263 K

The final volume is smaller.

Explanation:

Step 1: Given data

  • Initial temperature (T₁): 30 °C
  • Initial volume (V₁): 3.25 L
  • Final temperature (T₂): -10 °C
  • Final volume (V₂): ?

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

T₁: K = 30°C + 273.15 = 303 K

T₂: K = -10°C + 273.15 = 263 K

Step 3: Calculate the final volume of the balloon

Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 3.25 L × 263 K/303 K = 2.82 L

7 0
3 years ago
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