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3 years ago

Your percent yield is 80%. The actual amount of product produced was 29.1

Chemistry

2 answers:

erastovalidia [21]3 years ago

8 0

Answer: 36.3 grams

Hope this helps

wlad13 [49]3 years ago

8 0

Answer:

The answer to your question is Theoretical yield = 36.38 g

Explanation:

Data

Percent yield = 80%

Actual amount = 29.1 g

Theoretical yield = ?

Process

1.- Write the formula to calculate the Percent yield

Percent yield = Actual yield / Theoretical yield x 100

2.- Solve for Theoretical yield

Theoretical yield = Actual yield / percent yield x 100

3.- Substitution

Theoretical yield = 29.1 / 80 x 100

4.- Simplification

Theoretical yield = 36.38 g

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Answer: The value of i is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

Explanation:

The equation used to calculate the Vant' Hoff factor in dissociation follows:

$\alpha =\frac{i-1}{n-1}$

where,

$\alpha$ = degree of dissociation = 40% = 0.40

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Putting values in above equation, we get:

$0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4$

The equation used to calculate the degee of dissociation follows:

$\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}$

Total number of particles taken = 100

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Putting values in above equation, we get:

$0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40$

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

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2 years ago

40 g of CaCO3 is how many moles of CaCO3? 10 moles 0.4 moles 40 moles 100 moles

AleksandrR [38]

Answer:

0.4 moles

Explanation:

To convert between moles and grams you need the molar mass of the compound. The molar mass of of CaCO3 is 100.09g/mol. You use that as the unit converter.

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This rounds to 0.4 moles CaCO3

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3 years ago

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Answer:

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Explanation:

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3 years ago

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Answer:

Explanation:

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