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3 years ago

What are the main organs of the muscular system?

2 answers:

6 0

The muscular system is an organ system consisting of skeletal, smooth and cardiac muscles. It permits movement of the body, maintains posture and circulates blood throughout the body.

Ronch [10]3 years ago

6 0

Answer:

Skeletal, cardiac muscles.

Explanation:

It helps move the body around. Your welcome :)

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What is the weight on earth of a book with a mass of 1.5kg

Marta_Voda [28]

1.5x10
=15N

sorry if im wrong

8 0

3 years ago

Read 2 more answers

If 22.5L of nitrogen at 0.98 atm is compressed to 0.95 atm,what is the new volume?

Ksenya-84 [330]

At constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.

<h3>What is Boyle's law?</h3>

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given that;

Initial volume of the gas V₁ = 22.5L

Initial pressure of the gas P₁ = 0.98atm

Final pressure of the gas P₂ = 0.95atm

Final volume of the gas V₂ = ?

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = (0.98atm × 22.5L) / 0.95atm

V₂ = 22.05Latm / 0.95atm

V₂ = 23.2L

Therefore, at constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.

Learn more about Boyle's law here: brainly.com/question/1437490

#SPJ1

6 0

2 years ago

Easy points!

podryga [215]

The soda an air is most likely bubbling up and is going to explode.

3 0

3 years ago

A containing vessel holds a gaseous mixture of nitrogen and butane. Thepressure in the vessel at 126.9 Cis 3.0 atm. At 0 C, the

Viefleur [7K]

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

A vessel contains a gaseous mixture of nitrogen and butane. At 126.9 °C (400.1 K) the pressure is due to the mixture is 3.0 atm.

We can calculate the total number of moles using the ideal gas equation.

$P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{3.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.091 mol/L \times V$

At 0 °C (273.15 K), the pressure due to the gaseous nitrogen is 1.0 atm.

We can calculate the moles of nitrogen using the ideal gas equation.

$P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{1.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.030 mol/L \times V$