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damaskus [11]
3 years ago
13

What is the area of triangle UVW? (Scale factor question picture included)

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0
A= 320 cm2 and that is the answer
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9. A ladder of length 23 feet leans against the side of a building. The angle of elevation of the ladder is 76. Find the distanc
irakobra [83]

<h3><u>Answer:</u></h3>

  • B) 22.32 feet

\quad\rule{300pt}{1pt}

<h3><u>Solution</u><u>:</u></h3>

we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

\qquad\quad\bull ~{\boxed{\bf{ Sin\theta =\dfrac{Perpendicular}{Hypotenuse}}} }~\bull

Here,

  • hypotenuse = 23 feet
  • \theta = 76°
  • Value of Sin\theta = 0.97
  • Perpendicular = ?

\quad\dashrightarrow\quad \sf { sin\theta =\dfrac{P}{H}}

\quad\dashrightarrow\quad \sf { sin76° =\dfrac{P}{23}}

\quad\dashrightarrow\quad \sf { 0.97=\dfrac{P}{23}}

\quad\dashrightarrow\quad \sf {P = 0.97 \times 23 }

\quad\dashrightarrow\quad \sf { P = 22.32}

‎ㅤ‎ㅤ‎ㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>distance </u><u>from </u><u>the </u><u>top </u><u>of </u><u>the </u><u>ladder </u><u>to </u><u>the </u><u>ground </u><u>is </u><u>2</u><u>2</u><u>.</u><u>3</u><u>2</u><u> </u><u>feet </u><u>!</u>

\rule{300pt}{2pt}

4 0
3 years ago
Which choices are equivalent to the expression below? Check all that apply.
JulsSmile [24]

Answer:5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What number is at this position ?
Katarina [22]
The answer is 2.5 because the point is at the middle. Hope this’ll help
8 0
3 years ago
a 4.50 g coin of copper absorbed 54 calories of heat. what was the final temperature of the copper if the initial temperature wa
I am Lyosha [343]

The final temperature of copper is 155.43°C.

Step-by-step explanation:

The formula to apply is Q=m*Δt*c where ;

Q=heat energy, m=mass, c=specific heat capacity and Δt= change in temperature

Given that Q=54 calories , m=4.50 g and c=0.092 cal/g°C

In this question find Δt then ,the final temperature.

Δt=Q/m*c

Δt=54/4.50*0.092 =130.43°C

To find final temperature, apply the formula;

Δt=Final temperature - Initial temperature

130.43°C=Final temperature-25°C

130.43°C+25°C=Final temperature

155.43°C

Learn More

Specific Heat Capacity : brainly.com/question/12431744

Keyword : specific heat capacity

#LearnwithBrainly

3 0
4 years ago
Mr, Obrien needs to buy 8 television for the school. Each television costs $795. Mr. O'Brien has 120 fifty-dollar bills that he
Nina [5.8K]

Answer:

A. $6360, B. He doesn't have enough money.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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