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nexus9112 [7]
3 years ago
11

4X to the 3rd power + 6x to the second power minus x minus 12 minus x to the 4th power + 3x to the third power + 2 x to the seco

nd power + 3x + 1
Mathematics
1 answer:
galben [10]3 years ago
3 0

Ansexponents first. Do all of them. Then combine like terms altogether.  Then solve.

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Evaluate and simplify tan 15º.
dimulka [17.4K]
Tan(15) = tan(45 - 30) 

= [tan(45) - tan(30) ] / [ 1 + tan(30)tan(45)] 

= (1 - 1/sqrt(3)) /(1 + 1/sqrt(3)) 

= (sqrt(3) - 1)/(sqrt(3) + 1) 

= (sqrt(3) - 1)^2 /(3 - 1)

 = 1/2 [3 + 1 - 2sqrt(3) ] 

= (2 - sqrt(3) )

= 0.27 is your answer
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What is if you do 3x10
scZoUnD [109]

Answer:

30

Step-by-step explanation:

10 x 3 = 30

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artcher [175]
For a , C= 18.85
for b , C= 21.99
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3 years ago
Riley and Justin shared a cash prize in the ratio 2:5.justin received 27$ more than Riley.how much money did Riley get
anastassius [24]

Answer:

$18

Step-by-step explanation:

1. Subtract 5-2 to get three

2. Divide 27 by three to get 9. Now you know how many $ is in one sectio

3. Multiply 9 by 2

4. Riley got $18

4 0
3 years ago
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

t=2\cdot9.375=18.75

Hence, the rocket hits the ground after 18.75 seconds.

6 0
1 year ago
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