3.5 think of it as 3.0
C. ——
2.0
To perform a 90° rotation clockwise around the origin, you take the coordinates of the point A(x, y) and transform them to A'(y, -x). Since 180° and 270° are both "steps" of 90°, we can do this in succession and achieve our goal.
1) (5, 2) 90° = (2, -5) [(y, -x)]
2) (5, 2) 180° = two 90° turns = (2, -5) rotated 90° = (-5, -2)
3) (5, 2) 270° = three 90° turns = (-5, -2) rotated 90° = (-2, 5)°
4) (-5, 2) 90° = (y, -x) = (2, 5)
5) (-5, 2) 180° = two 90° turns = (2, 5) rotated 90° = (5, -2)
6) (-5, 2) 270° = three 90° turns = (5, -2) rotated 90° = (-2, -5)
7) (-2, 5) 90° = (y, -x) = (5, 2)
8) (5, -2) 180° = (y, -x) with another 90° turn = (-2, -5) rotated 90° = (-5, 2)
To solve this problem you must follow the proccedure shown below:
1. You have that <span>the pasture must contain 128 square meters and no fencing is required along the river. Then:
A=LxW
A is the area
L is the lenght
W is the width
2. Let's clear W:
W=A/L
W=128/L
3. The formula of the perimeter is:
P=2L+W
P=2L+(128/L)
4. Now, you must derivate:
dP/dL=0
2+(128/L</span>²)=0
<span> L=8 meters
W=A/L
W=128/8
W=16 meters
</span>
Answer:
x = 1/3
Step-by-step explanation:
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other:
21x = 7
Divide 21 from both sides:
(21x)/21 = (7)/21
x = 7/21
x = 1/3
x = 1/3 is your answer.
~
Ok so 1st, you do the (80 ÷ 20), then you get
10-4+(4)y^4
then you 10-4
6+(4)y^4
then....
(10)y^4
so then it's
10y^4
Unless there is a =, but if not it's 10y^4
