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Ganezh [65]
3 years ago
12

Yellowstone National Park has an average of about 4500 bison living in it. The park covers 3472 square miles. What is the popula

tion density of bison living in Yellowstone? a. 1.3 bison/mi2028 b. 16 bison/mi2028 c. 77 bison/mi2028 Dbison/mi2028
Chemistry
2 answers:
hoa [83]3 years ago
8 0

Ans) 1.3 bison/mile

Soln:} See according to the question, Yellowstone National Park has an average of about 4500 bison living in it.

Area covered by Yellowstone park is 3472 miles.

So, to find the density of bisons living in Yellowstone Park we have to divide the no. of bisons by given area.

= 4500/3472

which is approximately 1.3 bisons per mile.

Therefore option a) is correct

Hope it helps!!!

Vera_Pavlovna [14]3 years ago
5 0

Answer:

A

Explanation:

I took the test this morning

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attashe74 [19]

Answer:

I think it's either A or D I'm not sure hope that I helped you.

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3 years ago
I WIll upvote for answer<br> Balance the following reaction Fe^2 O ^3 +HCI-&gt;FeCI^3+H^2O
kotykmax [81]
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3 years ago
If 4.65 LL of CO2CO2 gas at 22 ∘C∘C at 793 mmHg mmHg is used, what is the final volume, in liters, of the gas at 35 ∘C∘C and a p
otez555 [7]

Answer:

About 7.9 L.

Explanation:

We can utilize the ideal gas law. Recall that:

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Because the amount of carbon dioxide does not change, we can rearrange to formula to:
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Because the right-hand side stays constant, we have that:
\displaystyle \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = nR

Hence substitute initial values and known final values:
\displaystyle \begin{aligned} \frac{(793\text{ mm Hg})(4.65 \text{ L})}{(22 \text{ $^\circ$C})} & = \frac{(743 \text{ mm Hg})V_2}{(35\text{ $^\circ$C})} \\ \\ V_2 & = 7.9\text{ L}\end{aligned}

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8 0
3 years ago
One of the following is not a factor which affect rates of reaction:
kotegsom [21]

Answer:

d. Pressure

Explanation:

Pressure is not a factor which affect rates of reaction.

However, surface area, temperature, and concentration are factors that affect rates of reaction.

8 0
3 years ago
What is the total number of sp2-hybridized carbon atoms present in the fluorophore used in the experiments
Mandarinka [93]

Answer:

9

Explanation:

The structure of fluorophore used in the experiments has been drawn in the attachment. And from the drawing counting we can say that there are 9 sp2-hybridized carbon atoms present. Fiuorophores are a fluorescent chemical compound that can re-emit light upon light excitation. Normally used to produce absorbance and emission spectra.

3 0
4 years ago
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