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Nady [450]
3 years ago
8

Formula of preparation of sodium hydroxide​

Chemistry
1 answer:
Umnica [9.8K]3 years ago
7 0

The chemical formula of sodium hydroxide is NaOH, and its molar mass is 40.01 g/mol. It is the alkali salt of sodium, and its structure is shown below:

It is an ionic compound consisting of sodium cation (Na+) and hydroxide (OH-) anion.

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2. Extract the relevant information from the question: NaOH V = 30 mL , M = 0.10 M HCl V = 25.0 mL, M = ?
Andrei [34K]

Answer:

0.12M

Explanation:

A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

HCl + NaOH —> NaCl + H2O

From the above equation,

nA (mole of the acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) = 30mL

Mb (Molarity of the base) = 0.1M

Va (volume of the acid) = 25mL

Ma (Molarity of the acid) =?

The molarity of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 25/ 0.1 x 30 = 1

Cross multiply to express in linear form

Ma x 25 = 0.1 x 30

Divide both side by 25

Ma = (0.1 x 30) / 25

Ma = 0.12M

The molarity of the acid is 0.12M

5 0
4 years ago
What is (part of life)and(art of life)?someone will answer me​
irinina [24]

Explanation:

Part of life is the role we certainly play during our role in life.Like a quote of shakespeare,we have our roles in earth to perform or we are like a chess whom we don't want to waste a move.

Art of life signifies that our life is wonderful with mysteries and hypotenic beauty and wonders and with different moments in a journey.

<em>Keep</em><em> </em><em>smiling </em><em>and</em><em> </em><em>hope</em><em> </em><em>u</em><em> </em><em>r</em><em> </em><em>satisfied </em><em>with</em><em> </em><em>my</em><em> </em><em>answer</em><em>.</em><em>Have</em><em> </em><em>a</em><em> </em><em>great</em><em> </em><em>day</em><em> </em><em>:</em><em>)</em>

7 0
3 years ago
Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C
umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}

Given:

\left[I_2_{Equilibrium} \right] = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}

So,

\left[I_{Equilibrium} \right]^2=0.011\times 0.10

\left[I_{Equilibrium} \right]^2=0.0011

\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

3 0
4 years ago
How many millimeters are equal to 0.399195L
WINSTONCH [101]
399.195 millimeters=0.399195 liters
3 0
3 years ago
Convert 55.6 km to m <br> show equation
crimeas [40]

Explanation:

1 km = 1000m

55.6 km = x m

x = 55.6*1000

x = 55600m

5 0
3 years ago
Read 2 more answers
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