P(at least 1 missed shot) = 100 - 77.6 = 22.4%
Number of times to expect al least 1 missed shot = 0.224 x 2500 = 560 times.
Answer: 6
Step-by-step explanation:
The greatest common factor is 2
This is because we start by taking the largest factor that goes into both coefficients. Since the first coefficient is 2, we have to try 2 and 1. Since 2 is larger and goes into 36 evenly, we use that.
Then we use the smallest number of each variable. There are 4 r's in both equations. So, that is the number that we take. There are 2 s's in the first term, so we take that number.
10.417 rounded to the nearest hundredth is 10.42
Hope it helps!