Question

If A = 8! and B = 8P8, then which one of the following is true:

Answer 1

Answer:

A. A = B

Step-by-step explanation:

Given

$A = 8!$

$B = ^8P_8$

Required

Which of the options is true

We start by simplifying $B = ^8P_8$

Permutation is calculated as follows

$^nP_r = \frac{n!}{(n - r)!}$

So.

$^8P_8 =\frac{8!}{(8 - 8)!}$

$^8P_8 =\frac{8!}{0!}$

0! = 1; So

$^8P_8 =\frac{8!}{1}$

$^8P_8 =8!$

Hence. B! = P!

This implies that $A = B = 8!$