<span>D) Eectrons in covalent bonds are not always shared equally.</span>
Answer:
answer is option 2 hope it helps
Answer:- 13.6 L
Solution:- Volume of hydrogen gas at 58.7 Kpa is given as 23.5 L. It asks to calculate the volume of hydrogen gas at STP that is standard temperature and pressure. Since the problem does not talk about the original temperature so we would assume the constant temperature. So, it is Boyle's law.
Standard pressure is 1 atm that is 101.325 Kpa.
Boyle's law equation is:
![P_1V_1=P_2V_2](https://tex.z-dn.net/?f=P_1V_1%3DP_2V_2)
From given information:-
= 58.7 Kpa
= 23.5 L
= 101.325 Kpa
= ?
Let's plug in the values and solve it for final volume.
![58.7Kpa*23.5L=101.325Kpa*V_2](https://tex.z-dn.net/?f=58.7Kpa%2A23.5L%3D101.325Kpa%2AV_2)
On rearranging the equation for ![V_2](https://tex.z-dn.net/?f=V_2)
![V_2=\frac{58.7Kpa*23.5L}{101.325Kpa}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7B58.7Kpa%2A23.5L%7D%7B101.325Kpa%7D)
= 13.6 L
So, the volume of hydrogen gas at STP for the given information is 13.6 L.
Answer:
- <u><em>1.7 × 10³ kg of ore.</em></u>
Explanation:
Call X the amount of aluminum ore mined to produce 1.0 × 10³ kg the aluminum metal.
Then, taking into account the yield of the reaction (82 % = 0.82) and the percent of aluminun in the ore (71% = 0.71), you can write the following equation:
- X × 71% × 82% = 1.0 × 10³ kg
↑ ↑ ↑ ↑
(mass of ore) (% of Al in the ore) (yield) ( Al metal to obtain)
You must just simplify, solve and compute:
- X = 1,000 / (0.71 × 0.82) = 1,000 / 0.5822 = 1,717.6 Kg
Round to two significant figures; 1,700 kg = 1.7 × 10³ kg of ore ← answer.
Hey mate!
Taxonomy is the <span>study of classification of organisms. Therefore, your answer is A.
Hope this helps!</span>