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The grams of glucose are needed to prepare 400g of a 2.00%(m/m) glucose solution g is calculated as below
=% m/m =mass of the solute/mass of the solution x100
let mass of solute be represented by y
mass of solution = 400 g
% (m/m) = 2% = 2/100
grams of glucose is therefore =2/100 = y/400
by cross multiplication
100y = 800
divide both side by 100
y= 8.0 grams
Sodium, hydrogen, carbon, and oxygen
Explanation: Sulphur trioxide forms Sulphur acid with water.
Phosphorus has unpaired electrons in 3p state
Answer:
A.
Explanation:
The paper clip allows elictricity to pass, unlike the eraser or paper
