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vivado [14]
3 years ago
14

How many grams of ice at -13 deg C must be added to 711 grams of water that is initially at a temperature of 87 deg C to produce

water at a final temperature of 10 deg C? Assume that no heat is lost to the surroundings and that the container has negligible mass.
Chemistry
1 answer:
Basile [38]3 years ago
4 0

Answer:

The answer to your question is m = 4.7 kg

Explanation:

Data

Ice                                   Water

mass = ?                          mass = 711 g

T₁ = -13°C                         T₁ = 87°C

T₂ = 10°C                         T₂ = 10°C

Ch = 2090 J/kg°K          Cw = 4180 J/kg°K

Process

1.- Convert temperature to kelvin

T₁ = 273 + (-13) = 260°K

T₁ water = 87 + 273 = 360 °K

T₂ = 10 + 273 = 283°K

2.- Write the equation of interchange of heat

                 - Heat lost = Heat absorbed

               - mwCw(T₂ - T₁) = miCi(T₂ - T₁)

-Substitution

              - 0.711(4180)(10 - 87) = m(2090)(10 - (-13))

- Simplification

                            228842.46 = 48070m

                            m = 228842.46/48070

-Result

                            m = 4.7 kg

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How many grams of NH3 can be produced from 12.0g of H2?
RSB [31]

Answer:

Balanced reaction:

3 H2 (g)  + N2 (g)  → 2 NH3 (g)

Use stoichiometry to convert g of H2 to g of NH3.  The process would be:

g H2 → mol H2 → mol NH3 → g NH3

12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3

Explanation: See above

Hope this helps, friend.

8 0
1 year ago
If the human body were a car, glucose would be:
NeTakaya
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8 0
2 years ago
If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form
Mumz [18]

he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

3 0
1 year ago
3. How many moles of silver is 8.46x1024 atoms of<br> silver?
ioda

Answer:

<h2>14.05 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.46 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 14.053156

We have the final answer as

<h3>14.05 moles</h3>

Hope this helps you

6 0
2 years ago
Help please its science
Nookie1986 [14]

Answer: any answer choices

Explanation:

6 0
2 years ago
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