This is a round robin style tournament. Given that there are 25 people, and order doesn't matter meaning that the combination AB is equivalent to BA you must use the choose formula.
Thus the answer should be 25C2 or
<em>25! / [(25-2)! * 2!] = 300</em>
Answer is C weak negavite
weak, because as the value became smaller that 1 the correlation weakens. negavite because it is a negative value (-0.23)
2.8 = 2 + 0.8
*let's analyze the decimal 0.8 as a fraction
0.8 = 8/10
*but if we divide the numerator and denominator by the same common factor of 2, we find that the fraction can be reduced to:
(8/2)/(10/2) = (4)/(5) = 4/5
*now evaluating the whole value of 2 (from the 2.8), we know there are a total of (5) - fifths in order to make a whole, so for 2 whole, we require:
2*(5/5) = (2*5)/5 = 10/5
*Now we add the fractions together:
2 = 10/5
0.8 = 4/5
10/5 + 4/5
*add numerators only, the denominator stays as a 5
(10 + 4)/5 = 14/5
*there are no common factors between 14 & 5 (other than 1, but that won't help reduce the fraction any), so the fraction is in it's simplest form:
answer is: 14/5
1.5 because 2/12=1/6 9 x (1/6) =1.5 gallons of water.
Juan's least integer scores in both tests will be 85 and 100 respectively.
- Test average of his two scores is atleast 92
Let :
- Score on test 1 = b
- Score on test 2 = b + 15
Average score can be related thus:
- (Sum of score ÷ number of test) ≥ 92
- (b + b + 15) ÷ 2 ≥ 92
- (2b + 15) ÷ 2 = 92
- 2b + 15 = 184
- 2b = 184 - 15
- 2b = 169
- b = 169 ÷ 2
- b = 84.5
Therefore, since both scores are integers, his least scores on both tests will be ::
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