Heat
gained or loss in a system can be calculated by multiplying the given mass to the
specific heat capacity of the substance and the temperature difference. It is
expressed as follows:<span>
Heat = mC(T2-T1)
When two objects are in contact,
it should be that the heat lost is equal to what is gained by the other. So, the heat released by the lead is equal to the heat that is absorbed by the water.
</span>Heat = mC(T2-T1) = 50.0 mL (1.00 g/mL) (4.18 J/g °C) (20 °C - 18 °C) = 418 J<span>
</span>
If a 3.50g sample of the hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate, the mass percent of water in the hydrate is 40%.
<h3>How to calculate mass percent?</h3>
The mass percent of hydrate in a sample can be calculated by dividing the mass of water in the sample by the mass of the hydrated compound.
According to this question, 3.50g sample of an hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate. The mass percent of water is calculated as follows:
Mass percent of water = (3.5-2.1)/3.5 × 100
Mass percent of water = 40%
Therefore, if a 3.50g sample of the hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate, the mass percent of water in the hydrate is 40%.
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Love the toradora pfp, also the answer to your question is...
answer: from newtons second law of motion,
F=ma hence,
F=20N
m=5kg so,
20=5×a
a=4m/s^2
Explanation:
Radioactive isotopes are unstable isotopes whose neutron/proton ratio differs from its stability ratio.
- These isotopes will naturally decay and break down on their own.
- A nucleus with neutron/proton ratio combination which is different different from its stability ratio will be unstable and split into one or more other nuclei.
- This is accompanied by the emission of small energetic particles.
Learn more:
Radioactive waste brainly.com/question/10125168
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