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hammer [34]
3 years ago
15

Suppose that two objects attract each other with a gravitational force of 32 Newtons. If the distance between the two objects is

doubled, what is the force of attraction between them?
Physics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

64N

Explanation:

32×2= 64N

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Use 3rd law to explain how a fish swims through water. Identify the force pairs and draw a diagram.
vovikov84 [41]
Well as the fish swims he pushes the water behind him which in return push him forward
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The perceived loudness of a sound is measured in
diamong [38]
<h2>Answer: decibels </h2>

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However, given the amplitude of the measured elements in practice, its submultiple, the decibel, is used. That is, this quotient is a logarithmic expression, where 1dB=0.1B

5 0
3 years ago
Calculate the orbital period of a dwarf planet found to have a semimajor axis of a = 4.0x 10^12 meters in seconds and years.
padilas [110]

Explanation:

We have,

Semimajor axis is 4\times 10^{12}\ m

It is required to find the orbital period of a dwarf planet. Let T is time period. The relation between the time period and the semi major axis is given by Kepler's third law. Its mathematical form is given by :

T^2=\dfrac{4\pi ^2}{GM}a^3

G is universal gravitational constant

M is solar mass

Plugging all the values,

T^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.98\times 10^{30}}\times (4\times 10^{12})^3\\\\T=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.98\times10^{30}}\times(4\times10^{12})^{3}}\\\\T=4.37\times 10^9\ s

Since,

1\ s=3.17\times 10^{-8}\ \text{years}\\\\4.37\times 10^9\ s=4.37\cdot10^{9}\cdot3.17\cdot10^{-8}\\\\4.37\times 10^9\ s=138.52\ \text{years}

So, the orbital period of a dwarf planet is 138.52 years.

3 0
3 years ago
Which gas giant has a rotation axis so tilted that the planet rotated like a bowling ball as it orbits the sun?
Anestetic [448]
The answer to your question is OPTION B
3 0
3 years ago
A small object carrying a charge of -4.00 nC is acted upon by a downward force of 24.0 nN when placed at a certain point in an e
PIT_PIT [208]

Answer:

E  = -6 \  N/C

Generally given that the electric field is negative it mean that its direction is opposite to that of the force    

Explanation:

From the question we are told that

   The charge on the small object is Q = -4.00 \ nC =  -4.00 *10^{-9} \  C

   The force is  F  =  24  \ nN  =  24 *10^{-9} \  N

    Generally the magnitude of the electric  field is mathematically represented as

       E  =  \frac{F}{Q}

=>    E  =  \frac{ 24 *10^{-9}} {-4 *10^{-9 }}

=>     E  = -6 \  N/C

Generally given that the electric field is negative it mean that its direction is opposite to that of the force    

 

6 0
3 years ago
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