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Illusion [34]
2 years ago
9

Evaluate 9(-2) What’s the answer for this

Mathematics
1 answer:
34kurt2 years ago
3 0

Answer:

-18

Step-by-step explanation:

just multiply 9 and -2, and you'll get -18

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Mr. Berger is building a sandbox for his children. The sandbox is in the shape of a right rectangular prism. The area of the bas
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110.7 feet cubed

Step-by-step explanation:

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2 years ago
What sets does radical 12 belong to
adoni [48]

Step-by-step explanation: The square root of 12 is represented in the radical form as √12 which is equal to 2√3. Since, 2√3 cannot be further simplified, hence such roots are called surds.

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2 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
3 years ago
Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on
Goryan [66]

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

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3 years ago
In a dance competition, a participant has to score a total of at least 30 points in the first four rounds combined to move on to
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If he got 5 points in the first round and he needed at least thirty he would score 9 points in the next three rounds
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