<h3>Answer:</h3><h3>ok</h3><h3 /><h3 /><h3>Step By Step Explanation:</h3><h3>Cane sugar processing consists of the following steps: sugar cane is crushed, the juice is heated and filtered, then sent to a series of crystallization steps to create crystals of raw sugar, followed by centrifugation to remove any remaining juice or syrup.</h3>
Answer:The electron configuration of an atom shows the number of electrons in each sublevel in each energy level of the ground-state atom. To determine the electron configuration of a particular atom, start at the nucleus and add electrons one by one until the number of electrons equals the number of protons in the nucleus. Each added electron is assigned to the lowest-energy sublevel available. The first sublevel filled will be the 1s sublevel, then the 2s sublevel, the 2p sublevel, the 3s, 3p, 4s, 3d, and so on. This order is difficult to remember and often hard to determine from energy-level diagrams such as Figure 5.8
A more convenient way to remember the order is to use Figure 5.9. The principal energy levels are listed in columns, starting at the left with the 1s level. To use this figure, read along the diagonal lines in the direction of the arrow. The order is summarized under the diagram
Physical properties of metal include shiny, ductile, opaque, malleable and good conduction of heat and electricity
Answer:s the temperature is increased, fluoroantimonic acid decomposes and generates hydrogen fluoride gas (hydrofluoric acid). ... 1 Fluoroantimonic acid has a H0 (Hammett acidity function) value of -31.3. Dissolves glass and many other materials and protonates nearly all organic compounds (such as everything in your body)
tall me is this what you looking for
Answer:
Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)
Explanation:
In writing the cell notation for an electrochemical cell, the anode is written on the left hand side while the cathode is written on the right hand side. The two half cells are separated by two thick lines which represents the salt bridge.
For the cell discussed in the question; the Mn(s)/Mn^2+(aq) is the anode while the Co^2+(aq)/Co(s) half cell is the cathode.
Hence I can write; Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)