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iren2701 [21]
3 years ago
9

Find QN. Please show all the work on how you got your answer

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

QN = 28

Solution:

Given MNPQ is a parallelogram.

QT = 4x + 6 and TN = 5x + 4

To find the length of QN:

Let us solve it using the property of parallelogram.

Property of Parallelogram:

Diagonals of the parallelogram bisect each other.

Therefore, QT = TN

⇒ 4x + 6 = 5x + 4

Arrange like terms together.

⇒ 6 – 4 = 5x – 4x

⇒ 2 = x

⇒ x = 2

Substitute x = 2 in QT and TN

QT = 4(2) + 6 = 14

TN = 5(2) + 4 = 14

QN = QT + TN

      = 14 + 14

QN = 28

The length of QN is 28.

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Write an equation that represents the line. (-3,-6) and (2,-2) use exact numbers
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Given:

The line passes through (-3,-6) and (2,-2).

To find:

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If a line passes through two points (x_1,y_1)\text{ and }(x_2,y_2), then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through (-3,-6) and (2,-2). So, the equation of line is

y-(-6)=\dfrac{-2-(-6)}{2-(-3)}(x-(-3))

y+6=\dfrac{-2+6}{2+3}(x+3)

y+6=\dfrac{4}{5}(x+3)

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y=\dfrac{4}{5}(x)+\dfrac{12}{5}-6

y=\dfrac{4}{5}(x)+\dfrac{12-30}{5}

y=\dfrac{4}{5}(x)+\dfrac{-18}{5}

y=\dfrac{4}{5}(x)-\dfrac{18}{5}

Therefore, the equation of line is y=\dfrac{4}{5}(x)-\dfrac{18}{5}.

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