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jenyasd209 [6]
3 years ago
13

Which of the following compounds are ionic compounds? Check all of the boxes that apply.

Chemistry
2 answers:
Black_prince [1.1K]3 years ago
8 0

Answer:

CaCl2, MgO, and Na2O

Explanation:

just did it

lina2011 [118]3 years ago
5 0

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent

                

                Between 0.4 and 1.7 then it is Polar Covalent 

            

                Greater than 1.7 then it is Ionic

 

For CaCl₂,

                    E.N of Chlorine       =   3.16

                    E.N of Calcium        =   1.00

                                                   ________

                    E.N Difference              2.16          (Ionic Bond)


For C-H Bond in C₆H₁₂O₆,

                    E.N of Carbon            =   2.55

                    E.N of Hydrogen        =   2.20

                                                   ________

                    E.N Difference                 0.35         (Non-Polar Covalent Bond)


For C-O Bond in C₆H₁₂O₆,

                    E.N of Oxygen           =   3.44

                    E.N of Hydrogen        =   2.55

                                                   ________

                    E.N Difference                 0.89         (Polar Covalent Bond)


For O-H Bond in C₆H₁₂O₆,

                    E.N of Oxygen           =   3.44

                    E.N of Hydrogen        =   2.20

                                                   ________

                    E.N Difference                 1.24         (Polar Covalent Bond)


For MgO,

                    E.N of Oxygen              =   3.44

                    E.N of Magnesium        =   1.31

                                                   ________

                    E.N Difference                    2.13         (Ionic Bond)


For Na₂O,

                    E.N of Oxygen              =   3.44

                    E.N of Sodium              =   0.93

                                                   ________

                    E.N Difference                    2.51         (Ionic Bond)


For SiO₂,

                    E.N of Oxygen              =   3.44

                    E.N of Silicon                =   1.90

                                                   ________

                    E.N Difference                    1.54         (Polar Covalent Bond)


Result:

Compounds having Ionic Bonds are Na₂O, MgO and CaCl₂.

You might be interested in
Example of a stimulas and response in a organism
Goryan [66]

Answer:

Stimulus

Explanation:

Any change in an organism's environment that causes the organism to react. It is a scientific way of saying “cause”. Example: An animal is cold so it moves into the sun. Response: how the organism reacts to a stimulus and results in a change in behavior.

sorry if this isn't the answer you wanted

3 0
3 years ago
A mixture of CS2(g) and excess O2(g) is placed in a 10 L reaction vessel at 100.0 ∘C and a pressure of 3.10 atm . A spark causes
ziro4ka [17]

Answer:

PCO2  = 0.6 25 atm

PSO2  = 1.2 75 atm

PO2 = 0.6  atm

Explanation:

Step 1: Data given

Volume = 10.0 L

Temperature = 100.0 °C

Pressure = 3.10 °C

After reaction, the temperature returns to 100.0 ∘C, and the mixture of product gases (CO2, SO2, and unreacted O2) is found to have a pressure of 2.50 atm

Step 2: The balanced equation

CS2(g)+3O2(g)→CO2(g)+2SO2(g)

Step 3: Name the reactants and products

a = CS2

b = O2 before reaction

c = CO2

d = SO2

e = nS O2 after reaction with n = the number of moles

Step 4: Calculate moles before reaction

PV = nRT

n = PV/(RT)

(na + nb) = (3.10atm) * (10.0L) / ((0.08206 Latm/moleK) * (373.15K))

(na + nb) = 1.0124

Step 5: Calculate moles after reaction

PV = nRT

n = PV/(RT)

nc + nd + ne) = PV/(RT) = (2.50 atm)*(10.0L) / ((0.08206 Latm/moleK)*(373.15K))

(nc + nd + ne) = 0.816 moles

Step 6: Calculate mol fraction

For  1 mole CS2 we need 3 moles O2  to produce 1 mole of CO2 and 2 moles of SO2

moles O2 remaining = ne = nb - 3na

moles CO2 produced = nc = na

moles SO2 producted = nd = 2na

(nc + nd + ne) = 0.816 moles = nb - 3na + na + 2na = 0.816

nb = 0.816

. (na + nb) = 1.0124

na = 1.0124 moles - 0.816 moles = 0.208

which leads to  

nc = na = 0.208

nd = 2na = 2*0.208 = 0.416

ne = 0.816 - 3*0.208 = 0.192

mole fraction CO2 = 0.208 / (0.208 + 0.416 + 0.192) = 0.25

mole fraction SO2 = 0.416 / (0.208 + 0.416 + 0.192) = 0.5 1

mole fraction O2 = 0.192 /(0.208 + 0.416 + 0.192) = 0.24

Step 6: Calculate partial pressure

PCO2 = 0.25 * 2.50 atm = 0.6 25 atm

PSO2 = 0.51 * 2.50 atm = 1.2 75 atm

PO2 = 0.24 * 2.50 atm = 0.6  atm

Step 7: Control results

now let's verify a couple of things

PV = nRT

P = nRT/V

before rxn

P = (0.208 + 0.816) * (0.08206 L*atm/mole*K) * (373.15K) / (10.0L) ≈ 3.10 atm

after rxn

P = ((0.208 +0.416+0.192) * (0.08206 L*atm/mole*K) * (373.15K) / (10.0L) ≈ 2.50 atm

8 0
3 years ago
5)
Drupady [299]

What amount of heat absorbs 50 g of steel (ce = 0.115 cal / g. ° C) that

does its temperature vary by 25 ° C?

Answer:

143.75cal

Explanation:

Given parameters:

Mass of steel  = 50g

Specific heat capacity of the steel  = 0.115cal/g°C

Temperature  = 25°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat to cause this temperature change is dependent on mass and specific heat capacity of the substance.

  Amount of heat  = m C (ΔT)

m is the mass

c is the specific heat capacity

ΔT is the temperature change

 Now insert the parameters and solve;

  Amount of heat  = 50 x 0.115 x 25

  Amount of heat  = 143.75cal

4 0
2 years ago
What is the molality (m) of a solution that contains 76.5 g of KCl dissolved in 85.0 g of<br> water?
ladessa [460]

Answer:

76.5g KCl/74.55 grams per mole Kcl = x

molality= x/.085 kg H2O

Explanation:

well remember molality is moles of solute/kilograms of solvent. So it's the moles of KCl over 85 g of h20 converted into kg. if this makes sense.

5 0
3 years ago
Balancing chemical equations
kolbaska11 [484]

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

  aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

  B: 2a + 0b = 2c

  O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 2

  b = 3

  c = 2

4. Substitute Coefficients and Verify Result

  2B2 + 3O2 = 2B2O3

      L R

  B: 4 4 ✔️

  O: 6 6 ✔️

hope this helps!

7 0
2 years ago
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