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jenyasd209 [6]
3 years ago
13

Which of the following compounds are ionic compounds? Check all of the boxes that apply.

Chemistry
2 answers:
Black_prince [1.1K]3 years ago
8 0

Answer:

CaCl2, MgO, and Na2O

Explanation:

just did it

lina2011 [118]3 years ago
5 0

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent

                

                Between 0.4 and 1.7 then it is Polar Covalent 

            

                Greater than 1.7 then it is Ionic

 

For CaCl₂,

                    E.N of Chlorine       =   3.16

                    E.N of Calcium        =   1.00

                                                   ________

                    E.N Difference              2.16          (Ionic Bond)


For C-H Bond in C₆H₁₂O₆,

                    E.N of Carbon            =   2.55

                    E.N of Hydrogen        =   2.20

                                                   ________

                    E.N Difference                 0.35         (Non-Polar Covalent Bond)


For C-O Bond in C₆H₁₂O₆,

                    E.N of Oxygen           =   3.44

                    E.N of Hydrogen        =   2.55

                                                   ________

                    E.N Difference                 0.89         (Polar Covalent Bond)


For O-H Bond in C₆H₁₂O₆,

                    E.N of Oxygen           =   3.44

                    E.N of Hydrogen        =   2.20

                                                   ________

                    E.N Difference                 1.24         (Polar Covalent Bond)


For MgO,

                    E.N of Oxygen              =   3.44

                    E.N of Magnesium        =   1.31

                                                   ________

                    E.N Difference                    2.13         (Ionic Bond)


For Na₂O,

                    E.N of Oxygen              =   3.44

                    E.N of Sodium              =   0.93

                                                   ________

                    E.N Difference                    2.51         (Ionic Bond)


For SiO₂,

                    E.N of Oxygen              =   3.44

                    E.N of Silicon                =   1.90

                                                   ________

                    E.N Difference                    1.54         (Polar Covalent Bond)


Result:

Compounds having Ionic Bonds are Na₂O, MgO and CaCl₂.

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A 100.0 ml sample of 0.10 m ca(oh)2 is titrated with 0.10 m hbr. determine the ph of the solution after the addition of 400.0 ml
WINSTONCH [101]
The balanced equation for the reaction is as follows;
Ca(OH)₂ + 2HBr --> CaBr₂ + 2H₂O
stoichiometry of Ca(OH)₂ to HBr is 1:2
number of Ca(OH)₂ moles reacted - 0.10 mol/L x 0.1000 L = 0.010 mol
Number of HBr moles added - 0.10 mol/L x 0.4000 = 0.040 mol 
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therefore 0.010 mol of Ca(OH)₂  needs - 0.010 x 2 = 0.020 mol of HBr to be neutralised
but 0.040 mol of HBr has been added therefore number of moles of HBr in excess - 0.040 - 0.020 = 0.020 mol 
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HBr is a strong acid therefore complete ionization
[HBr] = [H⁺]
[H⁺] = 0.020 mol / (100.0 + 400.0 mL)
      = 0.020 mol / 0.5 L 
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pH = -log[H⁺] 
pH = - log [0.040 M]
pH = 1.40
pH of the medium is 1.40
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How does changing the amount of one substance affect a mixtures identity and a compounds identity iscience?
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Explanation:

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On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures  as atoms can be bonded in any proportion in a mixture.

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