<h2>
→
</h2>
Explanation:
Ethanol can be oxidized to ethanal or acetaldehyde which is further oxidized to acid that is acetic acid.
→ [oxidation by loss of hydrogen]
-
An oxidizing agent potassium dichromate(VI) solution is used to remove the hydrogen from the ethanol.
- An oxidizing agent used along with dilute sulphuric acid for acidification.
Acetaldehyde can also be reduced back to ethanol again by adding hydrogen to it by using a reducing agent that is sodium tetrahydro borate, NaBH4.
- The oxidation of aldehydes to carboxylic acids can be done by the two-step process.
- In the first step, one molecule of water is added in the presence of a catalyst that is acidic.
- There is a generation of a hydrate. (geminal 1,1-diol).
→ 
[reduction by the gain of electrons]
Here, the oxidizing agent used is
in the presence of acetone.
Answer:
81 °C
Explanation:
This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:
q = heat added/released by a sample
m = mass of sample
c=specific heat of sample
ΔT = change in temperature
from here we can rearrange the equation to state:
q/(mc) = ΔT
1200J/((20.0g)(4.2J/g•°C)) = ΔT
14°C = ΔT
If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.
The volume of a 200 g sample of gold is 9.76 cm³
<u><em> calculation</em></u>
volume = mass /density
mass = 200 g
volume = 20.5 g/Cm³
volume is therefore = 200g / 20.5 g/cm³ = 9.76 cm³
