Answer:62.66°C or 235.66K
Explanation:Q=McpT, the energy was given in calories so you first convert to Joules by multiplying the value in calories by 4.184J.
17*4.184=71.128kJ.
71.128kJ=mcpT
71.128kJ=245*4.187*(T-Tm)
Tm is the final temperature of the mixture. The T is the temperature given which should be converted to Kelvin by adding 273...T=32+273=305K.
71128J=245*4.187*(305-Tm)
71128=312873.575-1025.815Tm
1025.815Tm=312873.575-71128
1025.815Tm=241745.58
Tm=241745.58/1025.815
Tm=235.66K
B. a nucleus with a positive charge.
The correct answer among the choices is the last option. <span>Green light has a higher frequency than orange light. Frequency is inversely proportional to wavelength. G</span>reen has wavelengths ranging form 495 to 570 nm and orange has wavelengths ranging from 590 to 620 nm. Speed is said to be directly proportional with wavelength. Higher wavelength means more faster light.
Answer:
<u>thermal conductivity:</u> the rate at which heat is transferred by conduction through a unit cross-section area of a material, when a temperature gradient exits perpendicular to the area
<u>electrical conductivity:</u> the measure of the amount of electrical current a material can carry or it's ability to carry a current
<u>solubility:</u> the ability to be dissolved, especially in water
<u>magnetism:</u> a physical phenomenon produced by the motion of electric charge, resulting in attractive and repulsive forces between objects
<u>melting point:</u> the temperature at which a given solid will melt.
<u>boiling point:</u> the temperature at which a liquid boils and turns to vapor
Explanation:
hope this helps :D pls mark brainliest :D
<h3><u>Answer</u>;</h3>
1.0875 x 10-2 atm
<h3><u>Explanation;</u></h3>
2O3(g) → 3O2(g)
rate = -(1/2)∆[O3]/∆t = +(1/3)∆[O2)/∆t
The average rate of disappearance of ozone ... is found to
be 7.25 × 10–3 atm over a certain interval of time.
This means (ignoring time)
∆[O3]/∆t = -7.25 × 10^–3 atm
(it is disappearing, thus the negative sign)
rate = -(1/2)∆[O3]/∆t
rate = -(1/2)*(-7.25 × 10^–3 atm)
= 3.625 × 10^–3 atm
Now use the other part of the expression:
rate = +(1/3)∆[O2)∆t
3.625 × 10–3 atm = +(1/3)∆[O2)/t
∆[O2)/∆t = (3)*(3.625× 10^–3 atm)
= 1.0875 x 10-2 atm over the same time interval
