Answer:
y≤3
Step-by-step explanation:
5y+4≤22−y
<em>Step 1: Simplify both sides of the inequality.</em>
5y+4≤−y+22
<em>Step 2: Add y to both sides.</em>
5y+4+y≤−y+22+y
6y+4≤22
<em>Step 3: Subtract 4 from both sides.</em>
6y+4−4≤22−4
6y≤18
<em>Step 4: Divide both sides by 6.</em>
6y/6≤18/6
y≤3
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
y = x² - 4x + 4
0 = x² - 4x + 4
0 = x² - 2x - 2x + 4
0 = x(x) - x(2) - 2(x) - 2(-2)
0 = x(x - 2) - 2(x - 2)
0 = (x - 2)(x - 2)
0 = (x - 2)²
0 = x - 2
+ 2 + 2
2 = x
(x, y) = (2, 0)
The answer is 49 because it is
Step 1 distribute the 5 across (8+0.2)
6^3+5(8+0.2)
6^3+40+1
6^3+41 (<em>I simplified the +40 and the +1</em>)
Step 2 take 6 to the power of 3
6^3+41
6x6x6 6x6=36 36x6=216
216+41 (<em>Simplify!</em>)
257
I hope this helped!
