All categories

3 years ago

Is the following nuclear equation balanced? 237 Np - He+233 AM

Chemistry

1 answer:

Flura [38]3 years ago

6 0

Answer:

Yes

Explanation:

Np²³⁷ → He⁴ + Am²³³

The given nuclear equation is balanced. Np²³⁷ undergoes alpha decay and produce alpha particle and Am²³³.

Properties of alpha radiation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴ + energy

You might be interested in

The atomicity of bromine is

aev [14]

Answer:

So, the atomicity of noble gases is 1. Example. ... So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.

Explanation:

So, the atomicity of noble gases is 1. Example. ... So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.

could help

3 0

3 years ago

Cierta cantidad de gas ocupa 20 litros sometido a una presión de 1,5 atmósferas. Si lo comprimimos hasta 6 atmósferas, ¿qué volu

Mekhanik [1.2K]

Respuesta:

5 L

Explicación:

Paso 1: Información provista

Presión inicial (P₁): 1,5 atm

Volumen inicial (V₁): 20 L

Presión final (P₂): 6 atm

Paso 2: Calcular el volumen final del gas

Si asumimos temperatura constante y comportamiento ideal, podemos calcular el volumen final del gas (V₂) usando la Ley de Boyle.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1,5 atm × 20 L / 6 atm = 5 L

4 0

3 years ago

What does cellular respiration do?

Anton [14]

I believe the answer is A the 1st one

7 0

3 years ago

How does a catalyst speed up a chemical reaction

ser-zykov [4K]

By being an alternative route to the reaction with a lower activation energy.

5 0

3 years ago

Read 2 more answers

A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t

andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

$\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)$

Where:

μ (l): is the chemical potential of 2-propanol in solution

μ° (l): is the chemical potential of pure 2-propanol

R: is the gas constant = 8.314 J K⁻¹ mol⁻¹

T: is the temperature = 82.3 °C = 355.3 K

x: is the mole fraction of 2-propanol = 0.41

$\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)$

$\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}$

$\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}$

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.

I hope it helps you!

8 0

4 years ago