Answer:
A. 1.806x10^24 molecules of Pb(NO3)2
B. 18 oxygen atoms.
C. 2 moles of Al(NO3)3.
D. The mole ratio of Pb(N03)2 to Al(N03)3 is 3 : 2
Explanation:
The balanced equation for the reaction is given below:
2Al(s) + 3Pb(NO3)2(aq) —> 2Al(NO3)3(aq) + 3Pb (s)
A. Determination of the number molecules of Pb(NO3)2 used in the reaction. This is illustrated below.
From the balanced equation above, 3 moles of Pb(NO3)2 were used in reaction.
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of Pb(NO3)2 contains 6.02x10^23 molecules.
Now, if 1 mole of Pb(NO3)2 contains 6.02x10^23 molecules,
then, 3 moles of Pb(NO3)2 will contain = 3 x 6.02x10^23 = 1.806x10^24 molecules.
Therefore, 1.806x10^24 molecules of Pb(NO3)2 is used in the reaction.
B. Determination of the number of oxygen atom used in the reaction.
This is illustrated below:
To obtain the number of oxygen atom used in the reaction, we simply do a head count of the oxygen atom in the reactant.
The reactant containing oxygen is Pb(NO3)2 and there are 3 moles of it according to the balanced equation.
There are a total of 18 oxygen atom in 3 moles of Pb(NO3)2. Therefore, 18 oxygen atoms are used in the reaction.
C. Determination of the number of mole of Al(NO3)3 formed.
From the balanced equation above, 2 moles of Al(NO3)3 are formed
D. Determination of the mole ratio of Pb(N03)2 to Al(N03)3
From the balanced, 3 moles of Pb(N03)2 reacted and 2 moles of Al(N03)3 are produced.
Therefore, the mole ratio of Pb(N03)2 to Al(N03)3 is 3 : 2
