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ycow [4]
3 years ago
13

2Al(s)+ 3Pb(N03) 2(aq) 2Al(N03)3(aq) + 3Pb (s)How many molecules of Pb(N03) 2 are used in the reaction? How many oxygen atoms ar

e used in the reaction? How many moles of Al(N03)3 are formed? What is the mole ratio of Pb(N03) 2 to Al(N03)3?
Chemistry
1 answer:
beks73 [17]3 years ago
8 0

Answer:

A. 1.806x10^24 molecules of Pb(NO3)2

B. 18 oxygen atoms.

C. 2 moles of Al(NO3)3.

D. The mole ratio of Pb(N03)2 to Al(N03)3 is 3 : 2

Explanation:

The balanced equation for the reaction is given below:

2Al(s) + 3Pb(NO3)2(aq) —> 2Al(NO3)3(aq) + 3Pb (s)

A. Determination of the number molecules of Pb(NO3)2 used in the reaction. This is illustrated below.

From the balanced equation above, 3 moles of Pb(NO3)2 were used in reaction.

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of Pb(NO3)2 contains 6.02x10^23 molecules.

Now, if 1 mole of Pb(NO3)2 contains 6.02x10^23 molecules,

then, 3 moles of Pb(NO3)2 will contain = 3 x 6.02x10^23 = 1.806x10^24 molecules.

Therefore, 1.806x10^24 molecules of Pb(NO3)2 is used in the reaction.

B. Determination of the number of oxygen atom used in the reaction.

This is illustrated below:

To obtain the number of oxygen atom used in the reaction, we simply do a head count of the oxygen atom in the reactant.

The reactant containing oxygen is Pb(NO3)2 and there are 3 moles of it according to the balanced equation.

There are a total of 18 oxygen atom in 3 moles of Pb(NO3)2. Therefore, 18 oxygen atoms are used in the reaction.

C. Determination of the number of mole of Al(NO3)3 formed.

From the balanced equation above, 2 moles of Al(NO3)3 are formed

D. Determination of the mole ratio of Pb(N03)2 to Al(N03)3

From the balanced, 3 moles of Pb(N03)2 reacted and 2 moles of Al(N03)3 are produced.

Therefore, the mole ratio of Pb(N03)2 to Al(N03)3 is 3 : 2

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SVEN [57.7K]

Answer:

Q = 10.8 KJ

Explanation:

Given data:

Mass of Al= 100g

Initial temperature = 30°C

Final temperature = 150°C

Heat required = ?

Solution:

Specific heat of Al = 0.90 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 150°C - 30°C

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Q = 100g×0.90 J/g.°C× 120°C

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4 0
3 years ago
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A reaction at -6.0 °C evolves 786. mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is co
borishaifa [10]

Answer:

V of Sulfur tetrafluoride is  17.2 L

Explanation:

Given data;

T = -6°C =  267K                                [1° C  = 273 K]

n = 786 mmol of SF4 which is 0.786 mol

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from ideal gas law  we have

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V = \frac{nRT}{P}V = \frac{0.786 mol \times 0.082 atmL/mol K \times* 267K}{1atm} = 17.2 L

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6 0
3 years ago
The pressure on 2.50 L of gas is changed from 4.5 atm to 2.2 atm. What is the new volume of gas?
swat32

Answer:

<h2>5.11 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

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8 0
3 years ago
Which mixture would be best to use as a wash for removal of the alkylcatechol from skin exposed to poison ivy?water and baking s
Rudiy27

The question is incomplete. Here is hte complete question.

The components of poison ivy and poison oak that produce the characteristic itchy rash are cathecols substituted with long-chain alkyl groups. The image is attached.

If you were exposed to poison ivy, which of the treatments below would you apply to the affected area? Justify your choice.

(a) Wash the area with cold water.

(b) Wash the area with dilute vinegar or lemon juice.

(c) Wash the area with sopa and water.

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Although lemon juice and vinegar are acids, they are weak acids and so, won't have a strong effect on the alkylcathecol.

As said before, alkyl is hydrophobic, so plain water won't affect in any way the cathecol.

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