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slamgirl [31]
3 years ago
6

QUESTION 7

Physics
2 answers:
harina [27]3 years ago
8 0

The term used is " WORK".

I'm really sorry it's not one of the choices.

kow [346]3 years ago
4 0

Just to add on to the previous answer, the type of energy that would be responsible for the movement of an object would be mechanical energy. The unit for mechanical energy is the exact same as the unit for work (the joule), meaning that they are very closely related.

Whenever there is an object experiencing work, mechanical energy must be present in order for such work to be done. Mechanical energy relates to both gravitational potential energy and kinetic energy.

AL2006 is correct that the term would be "work", however.

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What is the displacement of the object from 2 seconds to 6 seconds?
masya89 [10]

the answer would be 4

8 0
3 years ago
Read 2 more answers
An engineering firm is designing a ski lift. The wire rope needs to travel with a linear velocity of 2.0 meters per second, and
Mazyrski [523]

Answer:

The diameter of the bull-wheel is 3.82

Explanation:

Given that,

Velocity = 2.0 m/s

Angular velocity = 10 rev/m

\omega=10\times\dfrac{2\pi}{60}

\omega=1.0472\ rad/s

We need to calculate the diameter of bull-wheel

Using formula of angular velocity

v= r\omega

r=\dfrac{v}{\omega}

Put the value into the formula

r=\dfrac{2.0}{1.0472}

r=1.91\ m

The diameter of the bull-wheel

D=2r

D=2\times1.91

D=3.82\ m

Hence, The diameter of the bull-wheel is 3.82 m.

6 0
3 years ago
A charge of +3.0 mC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energ
Marat540 [252]

Answer:

Work done = 4584.9 J

Explanation:

given: q1=3.0 mC = 3.0 × 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 × 10⁻⁶ C

Solution:

Formula for the potential difference at the center of the circle

P.E = K × q1 q2 /r   (Coulomb's constant k= 8.99 × 10⁹ N·m² / C²)

P.E = 8.99 × 10⁹ N·m² / C² × 3.0 × 10⁻³ C × 34 × 10⁻⁶ C /  0.20 m

P.E =  4584.9 J = Work done

3 0
3 years ago
which one of the following is not an example of a combination reaction a. 2H2O(I)---> 2H2(g)+O2(g) b. 2K+CI2--->2KCI c. 2H
Alexxandr [17]
The answer would be A.

Combination reaction, otherwise known as synthesis reaction, occurs when two or more substances react and form a single, more complex substance.

A combination reaction looks like this in an equation:

                                     <em> A + B         </em><em>→       </em><em>AB</em>
                                   reactants              product

So from two reactants they become one product. 
Let's take a look at choice A.

                                   2H₂O(l)       →      2H₂(g) + O₂(g)
                                  reactant                     product(s)

Notice that from one substance, it broke down into two substances. So this is not a combination reaction. This is what you call a <em>decomposition reaction. </em>
6 0
3 years ago
A thin partition divides a thermally insulated vessel into a lower compartment of volume V and an upper compartment of volume 2V
Anni [7]

Answer:

1.89mol

Explanation:

The entropy change during free expansion is express as

S_{f}-S_{i}=nRln(\frac{V_{F}}{V_{I}})\\

Where S is the entropy of the system,

            n is the amount of mole

             R is the gas constant = 8.314 and

           V is the volume occupied at the initial and final stage

since the process is n adiabatic free expansion, the entropy of the system is constant. Hence we can re-write the equation as

S=nRln(\frac{V_{F}}{V_{I}})\\

where the  V_{i}=v\\ and V_{f}=2v+v=3v\\

S=17.28J/k\\ and

R=8.314\\

Now if we substitute in values we arrive at

17.28=(8.314)n*ln(\frac{3v}{v} )\\17.28=(8.314)n*ln(3 )\\17.28=(8.314)n*1.0986\\n=\frac{17.28}{8.314*1.0989}\\n=1.89 mole\\

6 0
3 years ago
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