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Gekata [30.6K]
3 years ago
8

P.E

Physics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

pagtalon?

Explanation:

because that had to be the answer

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The energy (such as light and heat) released by the Sun is produced by nuclear reactions in the core of the Sun, which convert h
Yanka [14]

Answer:

<em>the mass of one helium nucleus should be</em> <em>less than the mass of four hydrogen nuclei.</em>

Explanation:

Deep inside the core of the Sun, enough protons can collide into each other with enough speed that they stick together to form a helium nucleus and generate a tremendous amount of energy at the same time. This process is called nuclear fusion.

The mass-to-energy conversion is described by Einstein's famous equation:

E = mc2, or, in words, energy equals mass times the square of the velocity of light. Because the velocity of light is a very large number, this equation says that lots of energy can be gained from using up a modest amount of mass.

Photons In the proton-proton chain reaction, hydrogen nuclei are converted to helium nuclei through a number of intermediates. The reactions produce high-energy photons (gamma rays) that move through the "radiative layer" surrounding the core. This layer takes up 60 percent of the radius of the Sun. It takes a million years for energy to get through this layer into the "convective layer", because the photons are constantly intercepted, absorbed and re-emitted. In the core, the helium nuclei make up 62% of the mass (the rest is still hydrogen). The radiative and convective layers have about 72% hydrogen, 26% helium, and 2% heavier elements (by mass). The energy produced by fusion is then transported to the solar surface and emitted as light or ejected as high-energy particles.

3 0
3 years ago
The bright yellow light emitted by a sodium vapor lamp consists of two emission lines at 589.0 and 589.6 nm. What are the freque
stiv31 [10]

Answer:

Explanation:

Given

wavelength of emissions are

\lambda _1=589 nm

\lambda _2=589.6 nm

Energy is given by

E=\frac{hc}{\lambda }

where h=Planck's constant

x=velocity of Light

\lambda=wavelength of emission

E_1=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589\times 10^{-9}}

E_1=3.374\times 10^{-19} J

E_1 in kJ/mol

E_1=203.2 kJ/mol

frequency corresponding to this emission

\nu =\frac{c}{\lambda }

\nu _1=\frac{3\times 10^8}{589\times 10^{-9}}

\nu _1=5.09\times 10^{14} Hz

Energy corresponding to \lambda _2

E_2=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589.6\times 10^{-9}}

E_2=3.371\times 10^{-19} J

E_2=203.02 kJ/mol

frequency corresponding to this emission

\nu =\frac{c}{\lambda }

\nu _1=\frac{3\times 10^8}{589.6\times 10^{-9}}

\nu _1=5.088\times 10^{14} Hz

6 0
3 years ago
We want to get a better, more concrete idea of the strength of the electric force. So imagine you could remove all the electrons
Advocard [28]

Answer:

Explanation:

solution answered below

5 0
3 years ago
Read 2 more answers
Which of the following best represents a chemical reaction?
Sonja [21]

Answer:

The answer to your question should be D.

Explanation:

reactants are on the laft side of arrow and products are on right side of arrow

7 0
2 years ago
A car engine applies a force of 65,000 N, how much work is done by the engine as it pushed a car a distance of 75 m?
kupik [55]

Answer:

workdone = force \times distance \\  = 65000 \times 75 \\  = 4,875,000 \: J

3 0
2 years ago
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