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3 years ago

13

1. (3 points) Convert the given distances to kilometers using the

1 answer:

Lena [83]3 years ago

4 0

That’s a lot ........

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The velocity of a projectile at launch has a

arlik [135]

Answer:

1. 0 vh g

Explanation:

As air resistance is negligible, horizontal speaking, nothing is affecting the velocity. So the horizontal velocity of the projectile stays the same, vh.

As for vertical velocity, since there's always a constant gravitational acceleration acting downward, namely g, the vertical speed will decrease until it reaches the top where it is 0, it then starting to increase in magnitude, downward, due to its gravitational acceleration g.

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3 years ago

Who participates in sport more? women or men and why?

Katen [24]

More women ...........I'm not sure why

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3 years ago

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Which statement is true?

vivado [14]

Answer:

The speed of sound in air is not affected by the temperature

Explanation:

It just isn't™

4 0

3 years ago

An ecology center wants to set up an experimental garden using 400 meters of fencing to enclose a rectangular area of 9900 squar

blsea [12.9K]

Explanation:

Given that,

Fencing to be done, P = 400 m

Area of the rectangular garden, $A=9900\ m^2$

Let l is the length and b is the breadth of the garden. The area of the rectangle is given by :

$A=l\times b$

$lb=9900$ ............(1)

The perimeter of the garden is given by :

$P=2(l+b)$

$400=2(l+b)$

$200=(l+b)$ ...............(2)

On solving equation (1) and (2), we get the value of l and b are as follows :

l = 90 m and b = 110 m

or

b = 90 m and l = 110 m

So, the dimension of the garden is 90 m by 110 m. Hence, this is the required solution.

6 0

3 years ago

By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what

Vinil7 [7]

Explanation:

1. Mass of the proton, $m_p=1.67\times 10^{-27}\ kg$

Wavelength, $\lambda_p=4.23\times 10^{-12}\ m$

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

$\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}$

$V=\dfrac{h^2}{2q_pm_p\lambda^2}$

$V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}$

V = 45.83 volts

2. Mass of the electron, $m_p=9.1\times 10^{-31}\ kg$

Wavelength, $\lambda_p=4.23\times 10^{-12}\ m$

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

$\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}$

$V=\dfrac{h^2}{2q_em_e\lambda^2}$

$V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}$

$V=6.92\times 10^{34}\ V$

V = 84109.27 volt

Hence, this is the required solution.

7 0

4 years ago