Answer:
Explanation:
As we know that volume is given as
so it is given in liter as
now we have six pack of such volume
so total volume is given as
so its mass is given as
now the change in temperature is given as
now the heat given to the liquid is given as
Answer:
4. Parabola
Explanation:
The motion of the flight of the grenade is a projectile motion, it's shape is best illustrated using a parabolic diagram.
It's not a circle as the path is not totally round.
It's not an ellipse as the path of motion is not a a completely bounded shape.
Its not a hyperbola as a hyperbola is an open curve with two branches.
Its a parabolic shape because a parabola has just one branch
Answer:
v(t)= (d/dt)x(t)
Explanation:
The instantaneous velocity of an object is the limit of the average velocity as the elapsed time approaches zero, or the derivative of x with respect to t. Like average velocity, instantaneous velocity is a vector with dimension of length per time. The instantaneous velocity at a specific time point t
0 is the rate of change of the position function, which is the slope of the position function
x
(
t
)
at t
0
.
This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.
Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.
<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>
<em />
<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>
Answer:
If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface.
Explanation:
Option A is incorrect because, given this case, it is easier to calculate the field.
Option B is incorrect because, in a situation where the surface is placed inside a uniform field, option B is violated
Option C is also incorrect because it is possible to be a field from outside charges, but there will be an absence of net flux through the surface from these.
Hence, option D is the correct answer. "If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface."
