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HACTEHA [7]
3 years ago
7

A horizontal clothesline is tied between 2 poles, 12 meters apart. When a mass of 4 kilograms is tied to the middle of the cloth

esline, it sags a distance of 5 meters. What is the magnitude of the tension on the ends of the clothesline?

Physics
1 answer:
Olegator [25]3 years ago
6 0

Answer:

T=26.03 N

Explanation:

Given that

Distance between poles = 12 m

Mass of block m= 4 kg

Sag distance = 5 m

Lets take tension in the clothesline is T.

The component of tension in vertical direction will be T cosθ.

By force balancing

2 T cosθ = 40

here tan\theta =\dfrac{5}{6}

θ=39.80°

2 T cos39.8 = 40

T=26.03 N

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If a wave has a frequency of 74 Hz and a speed of 444 m/s, what is the wave's wavelength?
DaniilM [7]

Answer:

6 m

Explanation:

velocity = wavelength x frequency

444 m/s = wavelength x 74 Hz

444 m/s / 74 Hz = wavelength

wavelength = 6m

4 0
2 years ago
If you have a mechanical advantage of 2 with a block and tackle system.  How much force do you have to pull with?
Dovator [93]

Answer:

Half

Explanation:

You only have to exert a force equal to half the weight of the load to lift it.

7 0
3 years ago
Before beginning a long trip on a hot day, a driver inflates anautomobile tire to a gauge pressure of 2.70 atm at 300 K. At the
anygoal [31]

Answer:

The value is the temperature of the air inside the tire T_{2} = 340.54 K

% of the original mass of air in the tire should be released 99.706 %

Explanation:

Initial gauge pressure = 2.7 atm

Absolute pressure at inlet P_{1} = 2.7 + 1 = 3.7 atm

Absolute pressure at outlet P_{2} = 3.2 + 1 = 4.2 atm

Temperature at inlet T_{1} = 300 K

(a) Volume of the system is constant so  pressure is directly proportional to the temperature.

\frac{T_{2} }{T_{1} } = \frac{P_{2} }{P_{1} }

\frac{T_{2} }{300}  = \frac{4.2}{3.7}

T_{2} = 340.54 K

This is the value is the temperature of the air inside the tire

(b). Since volume of the tyre is constant & pressure reaches the original value.

From ideal gas equation P V = m R T

Since P , V & R is constant. So

m T = constant

m_{1}  T_{1} =  m_{2}  T_{2}

\frac{m_{2} }{m_{1}  } = \frac{T_{1} }{T_{2} }

\frac{m_{2} }{m_{1}  } = \frac{300}{354.54}

\frac{m_{2} }{m_{1}  } =0.00294

value of  the original mass of air in the tire should be released is  \frac{m_{2} - m_{1}}{m_{1}}

\frac{0.00294-1}{1}

⇒ -0.99706

% of the original mass of air in the tire should be released 99.706 %.

8 0
3 years ago
What is the differnce between kinetic and potential energy
Tems11 [23]
I think the answer should be that, Kinetic energy is contained in a moving object, while potential energy exists in a stored form.
5 0
3 years ago
Read 2 more answers
Waves of wavelength 24 cm and amplitude 3.0 em are used to create a standing wave. The distance from one node tothe next in the
NikAS [45]

Answer:

D. 12 cm

Explanation:

A node is a point on a standing wave that does not vibrate.

The nodes of a standing wave are shown in the following sketch.

The red dots are the nodes of the standing wave.

It is observed that the distance between two adjacent nodes is half the wavelength of the wave.

Therefore, if the wavelength of the wave is 24 cm, then the distance from one node to the net must be 24 / 2 = 12 cm.

Hence, choice D is the correct answer.

7 0
1 year ago
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