If the initial PE is mgh(initial) and the final PE is mgh(final) then mgh(initial)-mgh(final) should give you your change in PE.
So, without conversions your answer should be
[(.08)(9.8)(8)]-[(.08)(9.8)(6)]=change in PE which is 1.568Joules.
Answer
Given,
Sound Power, P = 600 W
a) Intensity of sound,
r = 5 m
we know,



I = 1.91 W/m²
b) Sound intensity

I₀ = 10⁻¹²


c) Sound experienced by the Phil
β₁ = 123 - 23 = 100 \ dB
distance from the sound
again using sound intensity formula



where, I = P/A


r = 69.09 m
Distance where Phil will experience same sound intensity without earplug is equal to r = 69.09 m
Answer:
1. The speed of infrared radiation is greater than radio wave radiation
2. The wavelength of infrared radiation is less than the radio wave radiation
Explanation:
Given:
The radio wave radiation N₁ is 3x10⁵ to 3x10⁷ Hz and the infrared radiation N₂ is 3x10¹¹ to 3x10¹⁴ Hz. The speed is:

1. The speed of infrared radiation is greater than radio wave radiation
2. The wavelength is:
λ = C/N
where more C, less λ
Then, the wavelength of infrared radiation is less than the radio wave radiation
checlknthfd sissExplanation: 2+3 ls g g fg
Answer:
In a collision, there is a collision force which endures for some amount of time to cause an impulse. This impulse acts upon the object to change its velocity and thus its momentum