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ahrayia [7]
3 years ago
5

In a standard title block, the size of the

Physics
1 answer:
jeyben [28]3 years ago
8 0
The correct answer is B: a set of dimensions
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A 0.080Kg robin, perched on a power line 6 m above the ground , swoops down to snatch a worm from the ground and then returns to
raketka [301]
If the initial PE is mgh(initial) and the final PE is mgh(final) then mgh(initial)-mgh(final) should give you your change in PE.
So, without conversions your answer should be
[(.08)(9.8)(8)]-[(.08)(9.8)(6)]=change in PE which is 1.568Joules.
4 0
3 years ago
A speaker at an open-air concert emits 600 W of sound power, radiated equally in all directions.
Marina86 [1]

Answer

Given,

Sound Power, P = 600 W

a) Intensity of sound,

    r = 5 m

   we know,

     I = \dfrac{P}{A}

     I = \dfrac{P}{4\pi r^2}

     I = \dfrac{600}{4\pi\times 5^2}

            I = 1.91 W/m²

b) Sound intensity

  \beta = 10 log(\dfrac{I}{I_0})

       I₀ = 10⁻¹²

  \beta = 10 log(\dfrac{1.91}{10^{-12}})

  \beta = 123\ dB

c) Sound experienced by the Phil

    β₁ = 123 - 23 = 100 \ dB

distance from the sound

again using sound intensity formula

  \beta = 10 log(\dfrac{I}{I_0})

  100= 10 log(\dfrac{I}{10^{-12}})

  I = 10^{-12}\times 10^{10}

where, I = P/A

  \dfrac{P}{4\pi r^2} = 10^{-2}

  r^2 = \dfrac{600}{0.04\times \pi}

        r = 69.09 m

Distance where Phil will experience same sound intensity without earplug is equal to r = 69.09 m

7 0
4 years ago
Infrared radiation has frequencies from 3.0×1011 to 3.0×1014 Hz, whereas the frequency region for radio wave radiation is 3.0×10
expeople1 [14]

Answer:

1. The speed of infrared radiation is greater than radio wave radiation

2. The wavelength of infrared radiation is less than the radio wave radiation

Explanation:

Given:

The radio wave radiation N₁ is 3x10⁵ to 3x10⁷ Hz and the infrared radiation N₂ is 3x10¹¹ to 3x10¹⁴ Hz. The speed is:

\frac{velocity_{2} }{velocity_{1} } =\frac{3x10^{11} }{3x10^{5} } to\frac{3x10^{14} }{3x10^{7} } =1x10^{6} to1x10^{7}

1. The speed of infrared radiation is greater than radio wave radiation

2. The wavelength is:

λ = C/N

where more C, less λ

Then, the wavelength of infrared radiation is less than the radio wave radiation

4 0
3 years ago
What are the
fiasKO [112]

checlknthfd sissExplanation: 2+3 ls g g fg

3 0
3 years ago
Why do you think the objects in each collision experience a different change in velocity?​
Sphinxa [80]

Answer:

In a collision, there is a collision force which endures for some amount of time to cause an impulse. This impulse acts upon the object to change its velocity and thus its momentum

8 0
3 years ago
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