(a) 10 GHz is the frequency of microwave radiation.
(b) 0.167 ms is required by the microwave to travel between two mountains.
Answer:
Explanation:
(a). 1 MHz is the frequency of microwave radiation.
(b) 0.167 ms is required by the microwave to travel between two mountains.
Answer:
Explanation:
a. Frequency is the measure of number of times a same thing will be repeated in a given time interval for a given time. And wavelength is the measure of distance between two successive crests or troughs. So wavelength and frequency are inversely proportional to each other. And velocity of light is the proportionality constant.
So frequency of microwave radiation = Speed of light/Wavelength of radiation
Frequency = 
Frequency = 
So 10 GHz is the frequency of microwave radiation.
b). As microwave is a part of light waves, so it will be experiencing the speed of light.
As the speed is 3*
m/s and the distance between the two mountains is given as 50 km, then time can be calculated as
Time = Distance/Velocity
Time = 
So time = 0.167 ms.
Thus, 0.167 ms is required by the microwave to travel between two mountains.
Updrafts and downdrafts in a thunderstorm interacting with wind shear
Answer:
vp = 0.94 m/s
Explanation
Formula
Vp = position/ time
position: Initial position - Final position
Position = 25 m - (-7 m) = 25 m + 7 m = 32 m
Then
Vp = 32 m / 34 seconds
Vp = 0.94 m/s
Answer:
W = 0.49 N
τ = 0.4851 Nm
Force
Explanation:
The weight force can be found as:
W = mg
W = (0.05 kg)(9.8 m/s²)
<u>W = 0.49 N</u>
The torque about the pivot can be found as:
τ = W*d
where,
τ = torque
d = distance between weight and pivot = 99 cm = 0.99 m
Therefore,
τ = (0.49 N)(0.99 m)
<u>τ = 0.4851 Nm</u>
The pivot exerts a <u>FORCE </u>on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.
Answer:
141.78 ft
Explanation:
When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.
Calculating the acceleration using one of Newton's equations of motion:
Note: The negative sign denotes deceleration.
When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2
Hence, we can find the minimum stopping distance using:
The minimum stopping distance is 141.78 ft.
