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Sliva [168]
3 years ago
8

onsider two projectiles that can be shot upward by spring guns. Object A is made of solid aluminum and has a mass of 50 grams. O

bject B is made of cast iron and has a mass of 200 grams. For this problem, you may take the gravitational field strength to be g = 10 N/kg. show answer Correct Answer 14% Part (a) Masses A and B are both shot straight upward at the same time. Mass A is shot with a speed of 2 m/s and mass B with a speed of 1 m/s. Which one hits the ground first?
Physics
1 answer:
BARSIC [14]3 years ago
8 0

Answer:

B

Explanation:

From Newton's law of motion, we have:

V^2 = U^2 + 2gH

Where V and U are final and initial velocity respectively.

H is the height.

For the object to have a sustain a maximum height it means the final velocity of the object is zero.

By computing the height of the object sustain by A, we have:

0^2 = 2^2 -2×10×H

0= 4 -20H

4 = 20H;

H= 0.2m

For object B we have;

0^2 = 1^2 -2×10×H

0 = 1 -20H

H = 1/20= 0.05m

From computing the height sustain by both objects, we see object B is projected at a shorter height into atmosphere than A.

Hence object B will return to the ground first.

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As a bat flies toward a wall at a speed of 6.0 m/s, the bat emits an ultrasonic sound wave with frequency 30.0 kHz. What frequen
Leto [7]

Answer:

f_b = 29.98 Hz

Explanation:

speed of bat = 6 m/s

sound wave frequency emitted by bat = 30.0 kHz

as we know,

speed of sound (c)= 343 m/s

f_w = f(\dfrac{c+v_r}{c+v_s})

f_w = 30(\dfrac{343+0}{343+6})

f_w = 29.48 Hz

now frequency received by bat is equal to  

f_b = f(\dfrac{c+v_r}{c+v_s})

f_b = 29.48(\dfrac{343+6}{343+0})

f_b = 29.98 Hz

hence the frequency hear by bat will be 29.98 Hz

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3 years ago
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Answer:

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I need help with one question on my homework. This is on the Specific Heat Capacity required practical.
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Answer:

will mostly accord at the top of the boiling water my kind sir

Explanation:

Evaporation takes place only at the surface of a liquid, whereas boiling may occur throughout the liquid. In boiling, the change of state takes place at any point in the liquid where bubbles form. The bubbles then rise and break at the surface of the liquid.

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Name 2 common methods of polymerization.
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Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​
gtnhenbr [62]

Answer:

"2Ω" is the net resistance in the circuit.

Explanation:

The given resistors are:

R1 = 3Ω

R2 = 6Ω

The net resistance will be:

⇒  \frac{1}{R_{net}} =\frac{1}{R_1} +\frac{1}{R_2}

On substituting the values, we get

⇒  \frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}

On taking L.C.M, we get

⇒  \frac{1}{R_{net}} =\frac{2+1}{6}

⇒  \frac{1}{R_{net}} =\frac{3}{6}

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On applying cross-multiplication, we get

⇒ R_{net}=2 \Omega

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3 years ago
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