Answer
current density is given by

where J = σ E

now,

a) Electric field strength at the inner surface of an iron cylinder
a = 0.5 cm = 0.005 m b = 2.3 = 0.023
L = 10 cm = 0.1 m I = 27 A


E = 8.59 x 10⁻⁴ V/m
b) Electric field strength at the outer surface of an iron cylinder
a = 0.5 cm = 0.005 m b = 2.3 = 0.023
L = 10 cm = 0.1 m I = 27 A


E =1.87 x 10⁻⁴ V/m
Answer:
0.65 m/s
Explanation:
Applying the equation,
v = u + at
35 = u + a×2.3 -(1)
Again, applying the equation,
s = ut +
a
41 = u×2.3 +
× 
35.65 = 2u + 2.3a -(2)
comparing first and second we get u= 0.65 m/s
Answer:
0.58 J
Explanation:
We know that Total energy is conserved.
Initial Kinetic energy + Initial potential energy = final kinetic energy+ final potential energy + dissipated heat energy
Initial kinetic energy = 0 ( magnet is at rest initially)
Initial Potential energy = m g h = (0.20 kg)(9.81 m/s²)(0.35 m) = 0.69 J
Final kinetic energy = 0.5 m v² = 0.5 ×0.20 kg × 1.10 m/s = 0.11 J
Final potential energy = 0
∴ Dissipated heat energy = (0.69 -0.11) J = 0.58 J
To solve this problem we will apply the concepts of Pythagoras to find the net path. An easy way is to graph the path to trace the path, which resembles that of a right triangle. The information provided is equivalent to that of the two short sides of the triangle, so we will find the longest side by the Pythagorean theorem. In this way,


Therefore the magnitude of the hummingbird’s total displacement is 3.12m