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3 years ago

Un tren de engranajes

Physics

2 answers:

OLEGan [10]3 years ago

7 0

The is the no way so it has to be 32

Virty [35]3 years ago

6 0

Answer:Un tren de engranajes es un sistema mecánico formado por el montaje de engranajes en un marco para que los dientes de los engranajes se acoplen.

Explanation:

La relación de los círculos de paso de los engranajes acoplados define la relación de velocidad y la ventaja mecánica del conjunto de engranajes. Un tren de engranajes planetarios proporciona una alta reducción de engranajes en un paquete compacto.

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Bingel [31]

The horizontal force is m*v²/Lh, where m is the total mass. The vertical force is the total weight (233 + 840)N.

Fx = [(233 + 840)/g]*v²/7.5 

v = 32.3*2*π*7.5/60 m/s = 25.37 m/s 

The horizontal component of force from the cables is Th + Ti*sin40º and the vertical component of force from the cable is Ta*cos40º 

Thh horizontal and vertical forces must balance each other. First the vertical components: 

233 + 840 = Ti*cos40º 

solve for Ti. (This is the answer to the part b) 

Horizontally 

[(233 + 840)/g]*v²/7.5 = Th + Ti*sin40º 

Solve for Th 

Th = [(233 + 840)/g]*v²/7.5 - Ti*sin40º 

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3 0

3 years ago

A hockey puck sliding along frictionless ice with speed v to the right collides with a horizontal spring and compresses it by 1.

patriot [66]

Answer:

The spring's maximum compression will be 2.0 cm

Explanation:

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Here we have a situation where the total mechanical energy of the system is conserved because there are no dissipative forces (there's no friction), so:

$E_{i}=E_{f}$

$K_{i}+U_{i}=K_{f}+U_{f}$

Note that at the initial moment where the hockey puck has not compressed the spring all the energy of the system is kinetic energy, but for a momentary stop all the energy of the system is potential elastic energy, so we have:

$K_{i} = U_{f}$

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Due conservation of energy the equality (1) has to be maintained, so if we let k and m constant x has to increase the same as v to maintain the equality. Therefore, if we increase velocity to 2v we have to increase compression to 2x to conserve the equality. This is 2(1.0) = 2.0 cm

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3 years ago

A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction

alukav5142 [94]

The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.
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6 0

4 years ago

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