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3 years ago

12

Un tren de engranajes

2 answers:

OLEGan [10]3 years ago

7 0

The is the no way so it has to be 32

Virty [35]3 years ago

6 0

Answer:Un tren de engranajes es un sistema mecánico formado por el montaje de engranajes en un marco para que los dientes de los engranajes se acoplen.

Explanation:

La relación de los círculos de paso de los engranajes acoplados define la relación de velocidad y la ventaja mecánica del conjunto de engranajes. Un tren de engranajes planetarios proporciona una alta reducción de engranajes en un paquete compacto.

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A container of gas is at a pressure of 3.7 x 10^5 Pa. How much work is done by the gas if its volume expands by 1.6 m^3 ?

Dmitriy789 [7]

Answer:

592000 J

Explanation:

We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:

1 Pa = 1 Kg/ms²

Therefore,

3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²

Next, we shall determine the workdone.

Workdone is given by the following equation:

Workdone (Wd) = pressure (P) × change in volume (ΔV)

Wd = PΔV

With the above formula, the work done can be obtained as follow:

Pressure (P) = 3.7×10⁵ Kg/ms²

Change in volume (ΔV) = 1.6 m³

Workdone (Wd) =?

Wd = PΔV

Wd = 3.7×10⁵ × 1.6

Wd = 592000 Kgm²/s²

Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:

1 Kgm²/s² = 1 J

Therefore,

592000 Kgm²/s² = 592000 J

Therefore, the Workdone is 592000 J.

6 0

3 years ago

Which statement best explains why Earth’s outer core is in liquid form? The iron-nickel alloy melts due to hot temperatures. The

amm1812

Answer:

A. The iron-nickel alloy melts due to hot temperatures.

Explanation:

7 0

3 years ago

Read 2 more answers

Joules constant, 4.1868 J/cal, is an equivalence relation for 4.1868 Joules of work for 1 calorie of heat delivered to a substan

Llana [10]

Answer:

The final answer is $6.1 BTU = 6.5621*103 KJ$

Explanation:

$1 BTU= 252 cal\\1 BTU =252 × 4.2 kJ\\6.1 BTU = 252 × 6.1×4.2 kJ = 6562.08 kJ\\ = 6.5621 × 103 kJ\\$

Hence, $6.1 BTU = 6.5621 × 103 kJ$

7 0

3 years ago

A point charge of +3 C is located at the origin of a coordinate system and a second point charge of -6 C is at x = 1.0 m. At w

Butoxors [25]

Answer:

The point at which the electrical potential is zero is x = +0.33 m.

Explanation:

By definition the electrical potential is:

$V_{E} = \frac{K*q}{r}$

Where:

K: is Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

r: is the distance

The point at which the electrical potential is zero can be calculated as follows:

$V_{1} + V_{2} = 0$

$K(\frac{q_{1}}{r_{1}} + \frac{q_{2}}{r_{2}}) = 0$ (1)

q₁ is the first charge = +3 mC

r₁ is the distance from the point to the first charge

q₂ is the first charge = -6 mC

r₂ is the distance from the point to the second charge

By replacing r₁ = 1 - r₂ into equation (1) we have:

$K(\frac{q_{1}}{1 - r_{2}} + \frac{q_{2}}{r_{2}}) = 0$ (2)

By solving equation (2) for r₂:

$r_{2} = \frac{q_{1}}{q_{1} - q_{2}} = \frac{3 mC}{3 mC - (-6 mC)} = +0.33 m$

Therefore, the point at which the electrical potential is zero is x = +0.33 m.

I hope it helps you!

8 0

3 years ago

Brainliest if correct Question 1 of 10

Art [367]

Answer:

B

Explanation:

hope this helps you

4 0

2 years ago