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gayaneshka [121]
3 years ago
11

Given d=60 miles and v=15 miles per hour, solve d=vt in terms of t, then substitute values.

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0

Given d=60 miles and v=15 miles per hour, solve d=vt in terms of t, then substitute values.

T=4hours

Is the answer

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If log10x=−3 , what is the value of x ?
IgorC [24]

log10x=−3

10 ^(log10x) = 10^(-3)

10x = 10^-3

x =10 ^ -3 / 10

x = 10^-4

x = .0001

x=1/ 10000

6 0
3 years ago
In studies for a​ medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.
timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

p = 0.03

q = 1 - 0.03 = 0.97

The mean is

\mu  = np

\mu = 643 \times 0.03 = 19.29

The standard deviation is

\sigma =  \sqrt{npq}

\sigma =  \sqrt{643 \times 0.03 \times 0.97}

\sigma =4.33

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \:  \frac{24.5 - 19.29}{4.33} ) \\  = P( 0.97\: < \: z \: < \:  1.20) \\  = 0.051

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

P(X \: < \: 24.5) = P(z \: < \:  \frac{24.5 - 19.29}{4.33} )  \\ =   P(z \: < \: 1.20)  \\  = 0.8849

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

P(X \: > \: 10.5) = P(z \: > \:  \frac{10.5 - 19.29}{4.33} )  \\ = P(z \: > \:  - 2.03)

= 0.9788

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

P(23.5  \:  <  \: X \:  <  \: 28.5) = P( \frac{23.5 - 19.29}{4.33}   \:  <  \: z \:  <  \:  \frac{28.5 - 19.29}{4.33} ) \\  = P( 0.97\:  <  \: z \:  <  \: 2.13) \\  = 0.1494

3 0
3 years ago
Please solve all and work needs to be shown ❤️❤️
Alex73 [517]

1).

a=bh

=(13)(9)

=117in^2

2).

A=1/2h(b1+b2)

=1/2(14)(15+9)

=168cm^2

3).

A=1/2d1d2

=1/2(18)(11)

=99in^2

4 0
3 years ago
Which story problem could be solved using the given equation? 14×35=m In Sophie’s doll collection, 35 of the dolls are in their
Sveta_85 [38]

The story problem of shawn's poster length and width is the correct one


5 0
3 years ago
Read 2 more answers
Marie has a total of $45 to spend at the grocery store. She has already spent $27. She wants to buy cases if soda tat cost $5 ea
pychu [463]

Answer:

3 cases

Step-by-step explanation:

45 - 27 = 18

18 ÷ 5 = 3

Tax is probably like $1 so It would add up to 18.

8 0
3 years ago
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