Answer:
20.4m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Distance = 53m
Time = 5.2s
Unknown:
Acceleration = ?
Solution:
This is a linear motion and we use the right motion equation;
S = ut + at²
S is the distance
u is the initial velocity
a is the acceleration
t is the time
Insert the parameters and solve;
53 = (0x 5.2) + x a x 5.2
53 = 2.6a
a = = 20.4m/s²
Answer:
Explanation:
It is given that,
Area of cross section of the pipe,
Area of cross section of the another pipe,
Speed of water in first pipe,
To find,
Speed of the water flowing in the second pipe.
Solve,
Let is the speed of water flowing in the second pipe. The relation between the area of cross section and the velocity is given by the continuity equation. It is given by :
Therefore, the water is flowing in the second pipe at the rate of 8 m/s.